从矩阵中找出一些行的算法，其和等于给定行

def find_rows(matrix, target):
    result = []
    path = []
    backtrack(matrix, target, path, 0)
    return result

def backtrack(matrix, target, path, row):
    if sum(matrix[i] for i in path) == target:
        result.append(path[:])
    
    for i in range(row, len(matrix)):
        path.append(i)
        backtrack(matrix, target, path, i + 1)
        path.pop()

# 示例矩阵
matrix = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9]
]
target = 9

result = find_rows(matrix, target)
print(result)