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判断数独板卡是否有效

数独板卡的有效性可以通过以下步骤进行判断:

  1. 验证每一行:检查每一行中的数字是否唯一,即没有重复的数字。可以使用一个长度为9的布尔数组来记录数字的出现情况,如果某个数字已经出现过,则该位置的布尔值为true,否则为false。遍历每一行,检查每个数字是否已经出现过,如果出现过则数独板卡无效。
  2. 验证每一列:类似于验证每一行,检查每一列中的数字是否唯一。同样使用一个长度为9的布尔数组来记录数字的出现情况,遍历每一列,检查每个数字是否已经出现过,如果出现过则数独板卡无效。
  3. 验证每一个小九宫格:数独板卡由9个小九宫格组成,每个小九宫格内的数字也必须是唯一的。可以使用一个长度为9的布尔数组来记录数字的出现情况,遍历每一个小九宫格,检查每个数字是否已经出现过,如果出现过则数独板卡无效。

如果以上三个步骤中的任意一个步骤发现有重复的数字,则数独板卡无效。如果三个步骤都通过验证,那么数独板卡有效。

数独板卡的有效性判断可以通过编写一个算法来实现。以下是一个示例的Python代码:

代码语言:txt
复制
def is_valid_sudoku(board):
    # 验证每一行
    for row in board:
        if not is_valid_row(row):
            return False
    
    # 验证每一列
    for col in range(9):
        column = [board[row][col] for row in range(9)]
        if not is_valid_row(column):
            return False
    
    # 验证每一个小九宫格
    for i in range(0, 9, 3):
        for j in range(0, 9, 3):
            square = [board[row][col] for row in range(i, i+3) for col in range(j, j+3)]
            if not is_valid_row(square):
                return False
    
    return True

def is_valid_row(row):
    seen = [False] * 9
    for num in row:
        if num != '.':
            index = int(num) - 1
            if seen[index]:
                return False
            seen[index] = True
    return True

# 测试代码
board = [
    ["5","3",".",".","7",".",".",".","."],
    ["6",".",".","1","9","5",".",".","."],
    [".","9","8",".",".",".",".","6","."],
    ["8",".",".",".","6",".",".",".","3"],
    ["4",".",".","8",".","3",".",".","1"],
    ["7",".",".",".","2",".",".",".","6"],
    [".","6",".",".",".",".","2","8","."],
    [".",".",".","4","1","9",".",".","5"],
    [".",".",".",".","8",".",".","7","9"]
]

print(is_valid_sudoku(board))  # 输出 True

在腾讯云的产品中,可以使用云函数(SCF)来实现数独板卡的有效性判断。云函数是一种无服务器的计算服务,可以根据事件触发执行代码。可以将上述判断数独板卡有效性的代码部署为一个云函数,通过调用云函数来判断数独板卡是否有效。

腾讯云函数(SCF)产品介绍链接地址:https://cloud.tencent.com/product/scf

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