偶然的是,我更新了我的ubuntu vp上的原型。现在,一些非常重要的python脚本不再工作了。速度不是很重要。我有两个解决方案:
TypeError: Descriptors cannot not be created directly.
If this call came from a _pb2.py file, your generated code is out of date and must be regenerated with protoc >= 3.19.0.
If you cannot immediately regenerate your protos, some
对于python:,这个问题已经得到解答。
但我很好奇,在ES6/ ES2015的Javascript中是否能做到这一点。
class A { ... }
class B extends A { ... }
class C extends A { ... }
let test = new B();
// ... After a while I want to have an instance of C instead of B in test.
这个是可能的吗?还是个坏主意?
每当我尝试导入tensorflow时,我都会得到这个错误
>>> import tensorflow
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/tensorflow/__init__.py", line 24, in <module>
from tensorflow.python import *
Fi
我在试着
from google.cloud import speech
但有错误
Traceback (most recent call last):
File "test.py", line 4, in <module>
from google.cloud import speech
File "/anaconda3/lib/python3.6/site-packages/google/cloud/speech.py", line 19, in <module>
from google.cloud.speech_v1 impo
无法将此setattr应用于_jpype._JClass对象
当我导入类型时,我会得到以下错误。
Traceback (most recent call last):
File "test.py", line 2, in <module>
import jpype
File "C:\Users\64837\AppData\Local\Programs\Python\Python38\lib\site-packages\jpype\__init__.py", line 20, in <module>
from ._c
在书中有一种叫做寄生组合继承的技术。我不明白为什么您需要获得原始原型的克隆,为什么不直接将SubType原型设置为父原型(SuperType)。
function object(o){
function F(){}
F.prototype = o;
return new F();
}
function inheritPrototype(subType, superType){
var prototype = object(superType.prototype); //create object -- why this is needed?
proto