,可以使用字典树(Trie)数据结构来解决这个问题。字典树是一种多叉树,每个节点代表一个字符,从根节点到叶子节点的路径表示一个单词。通过构建字典树,我们可以快速找到公共前缀最长的单词。
以下是解决这个问题的步骤:
以下是一个示例代码,用于实现上述步骤:
class TrieNode:
def __init__(self):
self.children = {}
self.is_word = False
class Trie:
def __init__(self):
self.root = TrieNode()
def insert(self, word):
node = self.root
for char in word:
if char not in node.children:
node.children[char] = TrieNode()
node = node.children[char]
node.is_word = True
def find_longest_common_prefix(self):
node = self.root
prefix = ""
while len(node.children) == 1 and not node.is_word:
char = list(node.children.keys())[0]
prefix += char
node = node.children[char]
return prefix
def find_longest_common_prefix_word(words):
trie = Trie()
for word in words:
trie.insert(word)
return trie.find_longest_common_prefix()
# 测试
words = ["apple", "application", "applet", "append", "app"]
result = find_longest_common_prefix_word(words)
print(result) # 输出 "app"
在这个例子中,词汇表中的单词是["apple", "application", "applet", "append", "app"],通过构建字典树并查找公共前缀,最长的公共前缀是"app"。
领取专属 10元无门槛券
手把手带您无忧上云