在Java中传递多个XPath时,在NodeList中查找节点编号,可以通过以下步骤实现:
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr1 = xpath.compile("//book/title");
XPathExpression expr2 = xpath.compile("//book/author");
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(new File("example.xml"));
NodeList nodeList1 = (NodeList) expr1.evaluate(doc, XPathConstants.NODESET);
NodeList nodeList2 = (NodeList) expr2.evaluate(doc, XPathConstants.NODESET);
int nodeNumber = -1;
for (int i = 0; i < nodeList1.getLength(); i++) {
if (nodeList1.item(i).isEqualNode(nodeList2.item(i))) {
nodeNumber = i;
break;
}
}
System.out.println("节点编号为:" + nodeNumber);
这样,你就可以在Java中传递多个XPath表达式,并在NodeList中查找节点编号了。
请注意,以上代码示例仅为演示目的,实际使用时需要根据具体情况进行适当的错误处理和异常处理。此外,对于XPath表达式的具体语法和使用方法,你可以参考相关的Java文档和教程进行深入学习。
领取专属 10元无门槛券
手把手带您无忧上云