在javascript中找到5000的阶乘是可能的吗

function factorialBigInt(n) {
    let result = 1n; // 使用BigInt
    for (let i = 2n; i <= n; i++) {
        result *= i;
    }
    return result;
}

const n = 5000n;
console.log(factorialBigInt(n).toString());

npm install big-integer

const bigInt = require("big-integer");

function factorialBigInt(n) {
    let result = bigInt(1);
    for (let i = 2; i <= n; i++) {
        result = result.multiply(i);
    }
    return result;
}

const n = 5000;
console.log(factorialBigInt(n).toString());

npm install bignumber.js

const BigNumber = require("bignumber.js");

function factorialBigNumber(n) {
    let result = new BigNumber(1);
    for (let i = 2; i <= n; i++) {
        result = result.multipliedBy(i);
    }
    return result;
}

const n = 5000;
console.log(factorialBigNumber(n).toFixed());