在python中查找某些时间范围内的时间重叠

from datetime import datetime

class TimeRange:
    def __init__(self, start_time, end_time):
        self.start_time = start_time
        self.end_time = end_time

def find_overlapping_ranges(ranges):
    overlapping_ranges = []
    length = len(ranges)
    for i in range(length):
        for j in range(i+1, length):
            if ranges[i].start_time < ranges[j].end_time and ranges[j].start_time < ranges[i].end_time:
                overlapping_ranges.append((ranges[i], ranges[j]))
    return overlapping_ranges

# 创建时间范围实例
range1 = TimeRange(datetime(2022, 1, 1, 9, 0), datetime(2022, 1, 1, 11, 0))
range2 = TimeRange(datetime(2022, 1, 1, 10, 0), datetime(2022, 1, 1, 12, 0))
range3 = TimeRange(datetime(2022, 1, 1, 13, 0), datetime(2022, 1, 1, 14, 0))

# 创建时间范围列表
ranges = [range1, range2, range3]

# 查找重叠的时间范围
overlapping_ranges = find_overlapping_ranges(ranges)

# 打印结果
for range_pair in overlapping_ranges:
    print("时间范围1：", range_pair[0].start_time, "-", range_pair[0].end_time)
    print("时间范围2：", range_pair[1].start_time, "-", range_pair[1].end_time)
    print("重叠时间范围：", max(range_pair[0].start_time, range_pair[1].start_time), "-", min(range_pair[0].end_time, range_pair[1].end_time))
    print()