如何合并两个实现相同但参数类型不同的方法

#include <iostream>

// 定义两个函数实现相同但参数类型不同
void merge(int a, int b) {
    std::cout << "Merging two integers: " << a << " and " << b << std::endl;
}

void merge(double a, double b) {
    std::cout << "Merging two doubles: " << a << " and " << b << std::endl;
}

int main() {
    merge(1, 2);        // 调用第一个函数
    merge(1.5, 2.5);    // 调用第二个函数

    return 0;
}

Merging two integers: 1 and 2
Merging two doubles: 1.5 and 2.5

#include <iostream>

// 定义一个函数模板
template<typename T>
void merge(T a, T b) {
    std::cout << "Merging two values: " << a << " and " << b << std::endl;
}

int main() {
    merge(1, 2);        // 调用时指定参数类型为int
    merge(1.5, 2.5);    // 调用时指定参数类型为double

    return 0;
}

Merging two values: 1 and 2
Merging two values: 1.5 and 2.5