如何在一个函数中组合两个ajax函数？

function ajaxRequest(url) {
  return new Promise((resolve, reject) => {
    const xhr = new XMLHttpRequest();
    xhr.open('GET', url);
    xhr.onload = () => resolve(xhr.responseText);
    xhr.onerror = () => reject(xhr.statusText);
    xhr.send();
  });
}

function combinedAjaxFunction() {
  ajaxRequest('https://api.example.com/data1')
    .then(data1 => {
      console.log('Data 1:', data1);
      return ajaxRequest('https://api.example.com/data2');
    })
    .then(data2 => {
      console.log('Data 2:', data2);
    })
    .catch(error => {
      console.error('Error:', error);
    });
}

combinedAjaxFunction();

async function ajaxRequest(url) {
  return new Promise((resolve, reject) => {
    const xhr = new XMLHttpRequest();
    xhr.open('GET', url);
    xhr.onload = () => resolve(xhr.responseText);
    xhr.onerror = () => reject(xhr.statusText);
    xhr.send();
  });
}

async function combinedAjaxFunction() {
  try {
    const data1 = await ajaxRequest('https://api.example.com/data1');
    console.log('Data 1:', data1);

    const data2 = await ajaxRequest('https://api.example.com/data2');
    console.log('Data 2:', data2);
  } catch (error) {
    console.error('Error:', error);
  }
}

combinedAjaxFunction();