如何在Java语言中对ArrayList中的带有键、值对的HashMap进行排序

import java.util.*;

public class HashMapSortExample {
    public static void main(String[] args) {
        ArrayList<HashMap<String, Integer>> list = new ArrayList<>();

        // 添加HashMap对象到ArrayList
        HashMap<String, Integer> map1 = new HashMap<>();
        map1.put("key1", 5);
        map1.put("key2", 3);
        list.add(map1);

        HashMap<String, Integer> map2 = new HashMap<>();
        map2.put("key1", 2);
        map2.put("key2", 7);
        list.add(map2);

        // 将ArrayList转换为数组
        HashMap<String, Integer>[] array = list.toArray(new HashMap[0]);

        // 自定义比较器类
        Comparator<HashMap<String, Integer>> comparator = new Comparator<HashMap<String, Integer>>() {
            @Override
            public int compare(HashMap<String, Integer> map1, HashMap<String, Integer> map2) {
                // 根据键值对的值进行比较
                int value1 = map1.get("key1");
                int value2 = map2.get("key1");
                return Integer.compare(value1, value2);
            }
        };

        // 对数组进行排序
        Arrays.sort(array, comparator);

        // 将排序后的数组转换回ArrayList
        ArrayList<HashMap<String, Integer>> sortedList = new ArrayList<>(Arrays.asList(array));

        // 打印排序后的ArrayList
        for (HashMap<String, Integer> map : sortedList) {
            System.out.println(map);
        }
    }
}