如何在Javascript函数中检查每个值是否满足条件？

function checkValues(arr, condition) {
  return arr.every(condition);
}

const numbers = [1, 2, 3, 4, 5];

// 检查所有数字是否大于0
const allPositive = checkValues(numbers, num => num > 0);
console.log(allPositive); // 输出: true

// 检查所有数字是否大于3
const allGreaterThanThree = checkValues(numbers, num => num > 3);
console.log(allGreaterThanThree); // 输出: false

function checkValues(arr, condition) {
  return arr.some(condition);
}

const numbers = [1, 2, 3, 4, 5];

// 检查是否有数字大于3
const someGreaterThanThree = checkValues(numbers, num => num > 3);
console.log(someGreaterThanThree); // 输出: true

// 检查是否有数字小于0
const someLessThanZero = checkValues(numbers, num => num < 0);
console.log(someLessThanZero); // 输出: false

function checkValues(arr, condition) {
  return arr.filter(condition);
}

const numbers = [1, 2, 3, 4, 5];

// 获取所有大于3的数字
const greaterThanThree = checkValues(numbers, num => num > 3);
console.log(greaterThanThree); // 输出: [4, 5]

function checkValues(arr, condition) {
  for (let i = 0; i < arr.length; i++) {
    if (!condition(arr[i])) {
      return false;
    }
  }
  return true;
}

const numbers = [1, 2, 3, 4, 5];

// 检查所有数字是否大于0
const allPositive = checkValues(numbers, num => num > 0);
console.log(allPositive); // 输出: true