如何在React Native中从实际应用程序中打开已安装的应用程序？

npm install react-native-linking --save

#import <React/RCTLinkingManager.h>

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
  // 其他代码...
  
  // 添加以下代码
  [RCTLinkingManager application:application didFinishLaunchingWithOptions:launchOptions];
  
  return YES;
}

- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url
  sourceApplication:(NSString *)sourceApplication annotation:(id)annotation
{
  return [RCTLinkingManager application:application openURL:url
                      sourceApplication:sourceApplication annotation:annotation];
}

- (BOOL)application:(UIApplication *)application continueUserActivity:(NSUserActivity *)userActivity
 restorationHandler:(void (^)(NSArray * _Nullable))restorationHandler
{
  return [RCTLinkingManager application:application
                   continueUserActivity:userActivity
                     restorationHandler:restorationHandler];
}

<intent-filter>
  <action android:name="android.intent.action.VIEW" />
  <category android:name="android.intent.category.DEFAULT" />
  <category android:name="android.intent.category.BROWSABLE" />
  <data android:scheme="你的自定义scheme" />
</intent-filter>

import { Linking } from 'react-native';

// 打开应用程序
Linking.openURL('你的自定义scheme://');