如何在TypeScript中编写递归函数来获取树结构中的顶层父级

interface TreeNode {
  id: string;
  parentId: string | null;
}

function getTopLevelParent(tree: TreeNode[], nodeId: string): string | null {
  // 递归实现获取顶层父级节点的逻辑
}

interface TreeNode {
  id: string;
  parentId: string | null;
}

function getTopLevelParent(tree: TreeNode[], nodeId: string): string | null {
  const currentNode = tree.find(node => node.id === nodeId);

  if (currentNode) {
    if (currentNode.parentId === null) {
      return currentNode.id;
    } else {
      return getTopLevelParent(tree, currentNode.parentId);
    }
  }

  return null; // 没有找到匹配的节点，返回null
}