如何在Typescript中强制多个参数使用一个类型？

// 定义一个接口
interface Person {
  name: string;
  age: number;
}

// 使用接口作为多个参数的类型
function greet(person: Person): string {
  return `Hello, ${person.name}! You are ${person.age} years old.`;
}

// 调用函数并传入符合接口定义的对象
const user = { name: 'Alice', age: 30 };
console.log(greet(user)); // 输出: Hello, Alice! You are 30 years old.

// 定义一个类型别名
type Person = {
  name: string;
  age: number;
};

// 使用类型别名作为多个参数的类型
function greet(person: Person): string {
  return `Hello, ${person.name}! You are ${person.age} years old.`;
}

// 调用函数并传入符合类型别名定义的对象
const user = { name: 'Alice', age: 30 };
console.log(greet(user)); // 输出: Hello, Alice! You are 30 years old.

function greet(person: Person): string {
  const name = person.name || 'Guest';
  const age = person.age || 0;
  return `Hello, ${name}! You are ${age} years old.`;
}

const user = { name: 'Alice' } as Person;
console.log(greet(user)); // 输出: Hello, Alice! You are 0 years old.