如何在plot中绘制Scatter3D中的超平面？

import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D

# 假设有100个三维数据点
n = 100
# 生成三维点的坐标，范围为[-1, 1]
x = np.random.rand(n) * 2 - 1
y = np.random.rand(n) * 2 - 1
z = np.random.rand(n) * 2 - 1
# 生成对应的标签，假设标签为0和1
labels = np.random.choice([0, 1], size=n)

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

# 绘制标签为0的散点
ax.scatter(x[labels == 0], y[labels == 0], z[labels == 0], c='r', marker='o')
# 绘制标签为1的散点
ax.scatter(x[labels == 1], y[labels == 1], z[labels == 1], c='b', marker='^')

# 假设超平面方程为2x + 3y - z + 4 = 0
# 生成超平面上的点
xx, yy = np.meshgrid(np.linspace(-1, 1, 10), np.linspace(-1, 1, 10))
zz = (2 * xx + 3 * yy + 4) / -1

# 绘制超平面
ax.plot_surface(xx, yy, zz, alpha=0.5)

ax.set_xlabel('X')
ax.set_ylabel('Y')
ax.set_zlabel('Z')
ax.set_title('Scatter3D with Hyperplane')

plt.show()