如何检查bash脚本的参数是否为“标志”

#!/bin/bash

# 遍历所有传入的参数
for arg in "$@"
do
  case $arg in
    -*) # 如果参数以短横线开头，则认为是标志
      echo "Found a flag: $arg"
      ;;
    *)  # 否则，认为是普通参数
      echo "Found an argument: $arg"
      ;;
  esac
done

#!/bin/bash

# 遍历所有传入的参数
for (( i=1; i<=$#; i++ ))
do
  arg="${!i}"
  if [[ $arg == -* ]]; then
    case $arg in
      -v|--verbose)
        echo "Verbose mode enabled"
        ;;
      -o|--output)
        ((i++))
        output="${!i}"
        echo "Output file: $output"
        ;;
      *)
        echo "Unknown flag: $arg"
        ;;
    esac
  else
    echo "Found an argument: $arg"
  fi
done