如何用php动态创建mysql表？

$servername = "数据库服务器地址";
$username = "数据库用户名";
$password = "数据库密码";
$dbname = "数据库名称";

// 使用mysqli扩展连接到MySQL数据库
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 使用PDO扩展连接到MySQL数据库
try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
    die("连接失败: " . $e->getMessage());
}

// 创建SQL语句
$sql = "CREATE TABLE users (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    name VARCHAR(30) NOT NULL
)";

// 使用mysqli扩展执行SQL语句
if ($conn->query($sql) === TRUE) {
    echo "表创建成功";
} else {
    echo "创建表时出错: " . $conn->error;
}

// 使用PDO扩展执行SQL语句
if ($conn->exec($sql) === TRUE) {
    echo "表创建成功";
} else {
    echo "创建表时出错: " . $conn->errorInfo();
}

$servername = "数据库服务器地址";
$username = "数据库用户名";
$password = "数据库密码";
$dbname = "数据库名称";

// 使用mysqli扩展连接到MySQL数据库
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 使用PDO扩展连接到MySQL数据库
try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
    die("连接失败: " . $e->getMessage());
}

// 创建SQL语句
$sql = "CREATE TABLE users (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    name VARCHAR(30) NOT NULL
)";

// 使用mysqli扩展执行SQL语句
if ($conn->query($sql) === TRUE) {
    echo "表创建成功";
} else {
    echo "创建表时出错: " . $conn->error;
}

// 使用PDO扩展执行SQL语句
if ($conn->exec($sql) === TRUE) {
    echo "表创建成功";
} else {
    echo "创建表时出错: " . $conn->errorInfo();
}

// 关闭数据库连接
$conn = null;