如何遍历xpath目标，每次添加22 - python

import requests
from lxml import etree

# 发送HTTP请求获取页面内容
url = "https://example.com"
response = requests.get(url)
html = response.text

# 使用lxml库解析HTML
tree = etree.HTML(html)

# 使用XPath定位目标元素
targets = tree.xpath("//target")

# 遍历目标元素并每次添加22
for target in targets:
    value = int(target.text) + 22
    target.text = str(value)

# 输出修改后的HTML
modified_html = etree.tostring(tree, encoding="utf-8").decode("utf-8")
print(modified_html)