将数据框中的多个值定义为缺失

import pandas as pd
import numpy as np

# 创建一个示例数据框
df = pd.DataFrame({'A': [1, 2, np.nan, 4],
                   'B': [5, np.nan, 7, 8],
                   'C': [9, 10, 11, np.nan]})

# 将数据框中的多个值定义为缺失值
df.replace([1, 7, 11], np.nan, inplace=True)

# 验证缺失值的定义
print(df)

     A    B     C
0  NaN  5.0   9.0
1  2.0  NaN  10.0
2  NaN  NaN   NaN
3  4.0  8.0   NaN

# 创建一个示例数据框
df <- data.frame(A = c(1, 2, NA, 4),
                 B = c(5, NA, 7, 8),
                 C = c(9, 10, 11, NA))

# 将数据框中的多个值定义为缺失值
df[which(df$A %in% c(1, 7, 11)), "A"] <- NA

# 验证缺失值的定义
print(df)

   A  B  C
1 NA  5  9
2  2 NA 10
3 NA  7 11
4  4  8 NA