将uint16_t数组转换为char数组- C++

#include <iostream>
#include <vector>
#include <cstdint>

// 假设我们有一个函数来检查当前系统的字节序
bool isLittleEndian() {
    int num = 1;
    return (*(char *)&num == 1);
}

// 将uint16_t数组转换为char数组
std::vector<char> uint16ToChar(const std::vector<uint16_t>& uint16Array) {
    std::vector<char> charArray;
    charArray.reserve(uint16Array.size() * sizeof(uint16_t));

    for (uint16_t value : uint16Array) {
        if (isLittleEndian()) {
            // 小端序系统，直接转换
            charArray.push_back((value & 0xFF));
            charArray.push_back((value >> 8) & 0xFF);
        } else {
            // 大端序系统，需要交换字节
            charArray.push_back((value >> 8) & 0xFF);
            charArray.push_back((value & 0xFF));
        }
    }

    return charArray;
}

int main() {
    std::vector<uint16_t> uint16Array = {0x1234, 0x5678};
    std::vector<char> charArray = uint16ToChar(uint16Array);

    for (char c : charArray) {
        std::cout << std::hex << (int)(unsigned char)c << " ";
    }
    std::cout << std::dec << std::endl;

    return 0;
}