我该如何处理C++中的不一致对象？

int a = 10;
double b = 3.14;

// 将整数a转换为double类型
double c = static_cast<double>(a);

// 现在a和b可以进行数学运算
double result = c + b;

class A {
public:
    int value;

    A(int v) : value(v) {}
};

class B {
public:
    double value;

    B(double v) : value(v) {}
};

A operator+(const A& a, const B& b) {
    return A(a.value + static_cast<int>(b.value));
}

int main() {
    A a(10);
    B b(3.14);

    // 使用重载的操作符将A和B对象相加
    A result = a + b;
}

template<typename T, typename U>
auto add(T a, U b) -> decltype(a + b) {
    return a + b;
}

int main() {
    int a = 10;
    double b = 3.14;

    // 使用模板函数将int和double类型的对象相加
    double result = add(a, b);
}

class Strategy {
public:
    virtual ~Strategy() {}
    virtual void execute() = 0;
};

class ConcreteStrategyA : public Strategy {
public:
    void execute() override {
        // 在这里实现策略A的代码
    }
};

class ConcreteStrategyB : public Strategy {
public:
    void execute() override {
        // 在这里实现策略B的代码
    }
};

class Context {
public:
    Context(Strategy* strategy) : strategy_(strategy) {}

    void execute() {
        strategy_->execute();
    }

private:
    Strategy* strategy_;
};

int main() {
    Context context(new ConcreteStrategyA());
    context.execute();
}