有没有可能在C中使用两个缓冲区精确地计算一个单词在文件中的出现频率？

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define BUFFER_SIZE 1024

int count_word_in_buffer(char *buffer, const char *word) {
    int count = 0;
    char *pos = buffer;
    size_t word_len = strlen(word);

    while ((pos = strstr(pos, word)) != NULL) {
        count++;
        pos += word_len;
    }

    return count;
}

int main() {
    FILE *file = fopen("example.txt", "r");
    if (!file) {
        perror("Failed to open file");
        return 1;
    }

    char buffer1[BUFFER_SIZE];
    char buffer2[BUFFER_SIZE];
    int total_count = 0;
    const char *word_to_count = "example";

    while (1) {
        size_t bytes_read1 = fread(buffer1, 1, BUFFER_SIZE, file);
        if (bytes_read1 == 0) break;

        total_count += count_word_in_buffer(buffer1, word_to_count);

        if (feof(file)) break;

        size_t bytes_read2 = fread(buffer2, 1, BUFFER_SIZE, file);
        if (bytes_read2 == 0) break;

        total_count += count_word_in_buffer(buffer2, word_to_count);
    }

    fclose(file);

    printf("The word '%s' appears %d times in the file.\n", word_to_count, total_count);

    return 0;
}