根据属性进行两个数组相交后返回object

function intersectArraysByProperty(arr1, arr2, property) {
  // Step 1: Sort arrays by property
  arr1.sort((a, b) => a[property] - b[property]);
  arr2.sort((a, b) => a[property] - b[property]);

  // Step 2: Initialize result array
  const result = [];

  // Step 3: Initialize pointers
  let pointer1 = 0;
  let pointer2 = 0;

  // Step 4-6: Intersect arrays by property
  while (pointer1 < arr1.length && pointer2 < arr2.length) {
    const obj1 = arr1[pointer1];
    const obj2 = arr2[pointer2];

    if (obj1[property] === obj2[property]) {
      result.push(obj1);
      pointer1++;
      pointer2++;
    } else if (obj1[property] < obj2[property]) {
      pointer1++;
    } else {
      pointer2++;
    }
  }

  // Step 7: Return result array
  return result;
}

// Example usage
const arr1 = [
  { id: 1, name: 'A' },
  { id: 2, name: 'B' },
  { id: 3, name: 'C' }
];

const arr2 = [
  { id: 2, name: 'B' },
  { id: 3, name: 'C' },
  { id: 4, name: 'D' }
];

const intersectedArray = intersectArraysByProperty(arr1, arr2, 'id');
console.log(intersectedArray);