计算python中两个列表元素之间的差异

list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]

# 差集
diff1 = set(list1) - set(list2)
diff2 = set(list2) - set(list1)

print("Elements only in list1:", diff1)
print("Elements only in list2:", diff2)

list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]

# 找出只在list1中的元素
diff1 = [x for x in list1 if x not in list2]

# 找出只在list2中的元素
diff2 = [x for x in list2 if x not in list1]

print("Elements only in list1:", diff1)
print("Elements only in list2:", diff2)

from collections import Counter

list1 = [1, 2, 3, 4, 1, 2]
list2 = [3, 4, 5, 6, 3, 4]

counter1 = Counter(list1)
counter2 = Counter(list2)

# 差异
diff = counter1 - counter2

print("Element frequency difference:", diff)

list1 = [[1, 2], [3, 4]]
list2 = [[3, 4], [5, 6]]

# 错误示例
# set(list1)  # TypeError: unhashable type: 'list'

# 正确示例
set1 = {tuple(x) for x in list1}
set2 = {tuple(x) for x in list2}

print(set1 - set2)

import multiprocessing as mp

def find_diff(list1, list2):
    return [x for x in list1 if x not in list2]

if __name__ == "__main__":
    list1 = range(1000000)
    list2 = range(500000, 1500000)

    with mp.Pool(mp.cpu_count()) as pool:
        result = pool.starmap(find_diff, [(list1, list2), (list2, list1)])

    print("Elements only in list1:", result[0])
    print("Elements only in list2:", result[1])