我有一个简单的C函数,其中,我让用户提供一个路径名,该函数检查它是否是有效的文件。
# include <stdio.h>
# include <string.h>
int main(void) {
char cFileChoice[256];
FILE * rInputFile;
unsigned int cFileLength;
printf("\nPlease supply a valid file path to read...\n");
fgets(cFileChoice, 255, stdin
我曾经访问过NNTP新闻组,我想知道如何识别以下NNTP头字符串
也就是说,这意味着什么?我在哪里/如何找到这些:
Injection-Info:logging-data="74569"
Message-ID: qjmbe4$28q9$1@adenine.netfront.net
X-Antivirus: AVG (VPS 190822-4, 22-08-2019)
Xref: news.netfront.net 24hoursupport.helpdesk:77925
X-Newsreader: Microsoft Windows Live Mail 16.4.3528.33
我有以下表达式:[^(\r\n)]*来识别任何不包含\r\n的文本。但是,当文本包含(或)时,则无法识别。
示例:
"I have following expression to recognize any text."将被确认为OK。
"I have following expression (A) to recognize any text."将不被识别。
因此,我想要全文:"I have following expression (A) to recognize any text."