这是我的代码:
$sql= "SELECT client.resID AS resID, client.resName AS resName, menu.id AS mid, menu.name ASmname, facilities.name AS fname, facilities.id AS fid FROM client INNER JOIN menu ON client.resID = menu.resIDINNER JOIN facilities ON client.resID =
$_";产出:
assign (resid 5 and name C ) (resid 87 and name CD or resid 85 and name CB or resid 94 andname C or resid 60 and name C or resid 152 and name C or resid 127 and name C or resid 159 and nameresid 135 and
免责声明:我是一个生物物理学家,对python没有先进的知识,我确实搜索过它和测试组合,比如:resid {}或.format(a) / ([a]) / (*a) / (x for x in a),但是我可能不知道该找什么投入:代码:for x in a[0:-1]: c=c+"resid {}".format(a[-1])
: (123.129, 177.253, 23.513) V131CG1/V135CG1/V78CG1assign (resid 5 and name C ) (resid87 and name CD or resid 85 and name CB or resid 94 and name CB or resid 32 and name CB or resid 21 and: (116.663, 177.052, 29.149) K87CD
我从另一个应用程序包的服务访问applicationInfo并通过packageManager获取资源,从而访问了它的布局。如果在布局中只指定了textView和按钮,它就可以正常工作。但如果在访问的布局中使用了任何可绘制资源,则抛出Resource not found Exception。ApplicationInfo info = packageManager.getApplicationInfo( packageName, 0 );
Resources res = packageManager.getResourcesForApplication( info );