RxJs。如果我有一个两个可观察值，如何抛出错误并继续发送值？

import { of, throwError, concat } from 'rxjs';
import { catchError } from 'rxjs/operators';

const observable1$ = of(1, 2, 3);
const observable2$ = throwError('Error occurred');

concat(
  observable1$,
  observable2$.pipe(catchError(error => {
    console.error(error);
    return of(); // 继续发送值，这里返回一个空的可观察值
  }))
).subscribe(
  value => console.log(value),
  error => console.error(error),
  () => console.log('Complete')
);