shifts-per-day should be a list (whose length matches the period length) containing how many shifts existFor example, if a period is 14 days, and there are 5 shifts on weekdays, and 2 shifts on weekends,[genes shifts-per-day]
我有一个这样的数组: num_vals = 3 for d in all_timeslots: for wind in range(0,11):
model.AddMultiplicationEquality(sq_r, [shifts[(n, wind)], shifts[(n, wind+1)],
SELECT * FROM shifts a SELECT shifts.date, shifts.time, max(shifts.barber_id) as 'barber_id' WHERE shifts.date = '2017-09-06' and shifts.is_free = true
GROUP BY shifts</em
假设我有以下模型: has_many :shifts @employees.joins("LEFT OUTER JOIN shifts ON employees.id = shifts.employee_id").where('shifts.starts_at BETWEEN ?, weekBegin, w