在list (Python3.4)的实现中,我看到了以下内容:
static int
list_resize(PyListObject *self, Py_ssize_t newsize)
{
PyObject **items;
size_t new_allocated;
Py_ssize_t allocated = self->allocated;
/* Bypass realloc() when a previous overallocation is large enough
to accommodate the newsize.
我有两个用于分配和释放计时器的函数。
分配计时器分配计时器,并将int返回给已分配的计时器
int allocate_timer(void)
{
int count = 0;
int allocated = 0;
/*Loop to find the first timer that is not allocated*/
for(count = 0; count< ARRAY_SIZE; count++)
{
if(allocated_timers[count] == '0')
{
给出的表称为休假2列,类型为varchar类型的Leavetype和数字类型的allocated_days。
请假:
离别型allocated_days病5例婚姻事故10例产妇90例
公司更新了它的政策,现在的变化是
请假:
leavetype allocated_days
sick add 5 days
marriage add 5 days
accident substract 5 days
maternity
Allocation of Race[3]~Brown County,Total:~6866,Allocated~315,Not allocated~6551
Allocation of Age[3]~Brown County,Total:~6866,Allocated~315,Not allocated~6551
Allocation of Race[3]~Boone County,Total:~6866,Allocated~315,Not allocated~6551
Allocation of Age[3]~Boone County,Total:~6866,Allocated~315,N
下面是剧本。
我想登录几个服务器并检查内核版本。
#!/bin/bash
#input server names line by line in server.txt
cat server.txt | while read line
do
sshpass -p password ssh root@$line << EOF
hostname
uname -r
EOF
done
我希望输出结果就像..。
server1_hostname
kernel_version
server2_hostname
kernel_version
以此类推。
我在server.txt中用大约80台服务器
今天我学习了Ruby垃圾收集,并做了一些测试
def count_allocated_objects
before = GC.stat(:total_allocated_objects)
yield
after = GC.stat(:total_allocated_objects)
after - before
end
count_allocated_objects {
s = "this is a string"
r = /[a-z]/
} # => 1, so only the string `s` be counted
count_
我在试图监控系统内存时遇到了一个问题,在加载位图之前,我试图猜测它是否适合内存。下面是我的代码:
public class MemoryCrashTestActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
String
int *getUserInput(FILE *fpin, int *elementCount) {
int *userInput;
// Load file into buffer
int length = fileLength(fpin);
char *buffer = (char *) malloc(length * sizeof(char));
int written = fread(buffer, sizeof(char), length, fpin);
// Number of int's allocated in userInput
int a
我在PostgreSQL中有这个函数,当我试图执行它时,我得到了这个错误消息:
ERROR: control reached end of function without RETURN
CONTEXT: PL/pgSQL function "SA_PRJ".usp_add_timesheet_record_neww(integer,integer,numeric,numeric,character varying,character varying)
我不确定,但我认为退货是问题所在,最后一定要退货吗?
CREATE OR REPLACE FUNCTION "
我试着做这个功能:
CREATE OR REPLACE FUNCTION "SA_PRJ".usp_verify_allocated_time(p_uid integer, p_project_id integer, p_allocated_time numeric, p_achieved_time numeric, p_task_desc character varying, p_obs character varying, p_date timestamp without time zone)
RETURNS void AS
$BODY$
declare alloc
我们有一个自动化,它可以登录到防火墙,并使用show nat pool命令列出所有NAT池和分配的连接。我们希望限制输出,如果可能的话,在show命令中只显示2或3 digit+。
我在想这是否可能?
来自show nat pool的示例输出:
TCP PAT pool xx-xxx-isp-transit, address xx.xx.xx.22(xx.xx.xx.157), range 1024-65535, allocated 100
TCP PAT pool xx-xxx-isp-transit, address xx.xx.xx.24(xx.xx.xx.188), range 1-1
我编写了一个很小的程序来粗略估计堆的大小(我知道我可能只是在googled上搜索它,但这看起来更有趣,我认为这将是一件快速简单的事情)。
这是整个节目:
#include <stdio.h>
#include <stdlib.h>
void main()
{
unsigned long long alloc_size = 1024;
unsigned long long total = 0;
unsigned int i = 0;
void* p = 0;
while(alloc_size >= 16) {