v[0] = 1;}In file included from /usr/local/gcc-4.8.1/include/c++/4.8.1/vector:62:0,/usr/local/gcc-4.8.1/include/c++/4.8.1/bits/stl_construct.h: In[with
但我仍然收到以下错误#include <thread> std::atomic<std::shared_ptr<int>> a = std::make_shared<int>(1);In file included from test.cc:1:
/usr/include/c++/10/atomic</
这项技术的用法示例可以在Antony Williams的"C++ Concurrency in Action“中看到,其中实现了一个无锁堆栈。堆栈被实现为具有std::atomic<node*>头指针的链表。在推送和弹出期间,在此指针上执行CAS操作。但是C++标准保证只有std::atomic_flag是无锁的,其他原子类型,包括std::atomic<T*>,可能不是无锁的。1)我的理解是否正确:如果std::atomic<T*>不是无锁
atomic-type-specifier: _Atomic ( type-name )这将导致以下代码:int (i2); // valid, same as i1 - usually seen in the context of pointer-to-function or pointer-to-array