int64的最大值：18446744073709551615 #include #include #include using namespace std...cout numeric_limits::min)() << endl; cout double: \t" double); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble>::min)() << endl; cout double: \t" numeric_limitsdouble>::min)() << endl; cout << "float: \t\t" << "所占字节数：" << sizeof
= std::numeric_limitsdouble>::min(); staticconstexprdouble MAX_NORMAL = std::numeric_limitsdouble>...)< epsilon; } // 相对误差检查 static bool isZeroRelative(double value) { if(std::abs(value)MIN_NORMAL){...() { double values[]={ 0.0, -0.0, 1e-15, 1e-10, std::numeric_limitsdouble>::min(), std...::numeric_limitsdouble>::denorm_min(), std::numeric_limitsdouble>::quiet_NaN(), std...::numeric_limitsdouble>::infinity() }; for(double val : values){ std::cout <<"Value: "<< val
::numeric_limitsdouble>::quiet_NaN()); log->addField("mae", std::numeric_limitsdouble>::quiet_NaN()); log->addField("time_learn", std::numeric_limitsdouble>::quiet_NaN...()); log->addField("time_learn2", std::numeric_limitsdouble>::quiet_NaN());...log->addField("time_learn4", std::numeric_limitsdouble>::quiet_NaN()); } //...task=" std::endl; std::cout min_target=" min_target std::endl;
::numeric_limitsdouble>::quiet_NaN()); log->addField("mae", std::numeric_limitsdouble>::quiet_NaN()); log->addField("time_learn", std::numeric_limitsdouble>::quiet_NaN...log->addField("time_learn4", std::numeric_limitsdouble>::quiet_NaN()); } //...task=" std::endl; std::cout min_target=" min_target std::endl;...在回归问题中，为预测值设置了最大的上限（std::max(min_target, p)）和最小的下限（std::min(max_target, p)）。
std::numeric_limits 在C/C++11中，std::numeric_limits为模板类，在库编译平台提供基础算术类型的极值等属性信息。...; int main(){ coutnumeric_limits::min()= "numeric_limits::min()<<endl; coutnumeric_limits...::max()= "numeric_limits::max()<<endl; coutnumeric_limits::min()= "numeric_limits...numeric_limitsdouble>::min()= "numeric_limitsdouble>::min()<<endl; coutnumeric_limitsdouble...>::max()= "numeric_limitsdouble>::max()<<endl; coutnumeric_limits::is_signed()= "numeric_limits
::max() numeric_limits::min() << endl; return 0; } 输出为： 在这个例子中，f 被初始化为一个单精度浮点数...案例演示： #include #include using namespace std; int main() { double d = 1.23456789...double>::max() numeric_limitsdouble>::min() << endl; return 0; } 输出为： 在这个例子中，d 被初始化为一个双精度浮点数...案例演示： #include #include using namespace std; int main() { long double ld = 1.23456789L...double>::max() numeric_limitsdouble>::min() << endl; return 0; } 输出为：
实例 #include #include using namespace std; int main() { cout numeric_limits::min)() << endl; cout double: \t" double); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble>::min)() << endl; cout double: \t" numeric_limitsdouble>::min)() << endl; cout << "float: \t\t" << "所占字节数：" << sizeof
signed与signed int与int是等价类型 #include #include #include using namespace std...>::max)(); cout numeric_limits::min)() << endl; // double...); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble...>::min)() << endl; cout double: \t" double); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble>::
cout numeric_limits::min)() << endl; cout double: \t" double); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble>::min)() << endl; cout double: \t" double); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble>::min)() << endl; cout << "float: \t\t" << "所占字节数：" << sizeof
numeric limits of int does exist static constexpr bool is_ specialized = true; static constexpr int min...、long double 当然你也可以为自己定义的数值类型定义一份特例化 四、numeric_limits提供的操作 numeric_limits定义在头文件中，下图列出了所有成员及其意义...::numeric_limits::max();float a[std::numeric_limits::max()]; round_style、has_denorm round_style...< endl; cout numeric_limits::max() double)" numeric_limits...double>::max() double)" numeric_limitsdouble>::max() << endl << endl
实例 #include #include using namespace std; int main() { cout numeric_limits::min)() << endl; cout double: \t" double); cout numeric_limitsdouble>::max)(); cout numeric_limitsdouble>::min)() << endl; cout double: \t" numeric_limitsdouble>::min)() << endl; cout << "float: \t\t" << "所占字节数：" << sizeof
if (task == 0) { p = std::min(max_target, p); p = std::max(min_target, p); mult...) {// 回归问题 p = std::min(max_target, p); p = std::max(min_target, p); grad_loss...= NULL) { log->addField("rmse_train", std::numeric_limitsdouble>::quiet_NaN()); log-...>addField("rmse_val", std::numeric_limitsdouble>::quiet_NaN()); log->addField("wmean",...std::numeric_limitsdouble>::quiet_NaN()); log->addField("wvar", std::numeric_limitsdouble>:
elapsed() const { return (double)(clock() - _start_time) / CLOCKS_PER_SEC; } double...elapsed_min() const { return (double)(1) / (double)CLOCKS_PER_SEC; } double elapsed_max...() const { return (double)(std::numeric_limits::max() - _start_time) / double(CLOCKS_PER_SEC...2.2 numeric_limits模版 说白了，它是一个模板类，它主要是把C++当中的一些内建型别进行了封装，比如说numeric_limits是一个特化后的类，从这个类的成员变量与成员函数中...&& _Right) { // construct by moving _Right _Myios::init(); _Myios::move(_STD
::array, std::cout, std::endl, std::vector; //算法依赖于C++ long double的精度，K的(M*N)次方不能大到有精度损失 constexpr..., M> generate_rand_individuality() { std::random_device rd; std::default_random_engine...return std::numeric_limitsdouble>::min(); } array, M> reproduce(const arraynumeric_limitsdouble>::min(): " std::numeric_limitsdouble>::min() << endl; cout std::numeric_limits...double>::max(): " std::numeric_limitsdouble>::max() << endl; //cout << (1 << 3); }
math.h> #include #include #define pi 3.1415926 #define NUM 10000 using namespace std...)num/NUM; return res; } int main() { double res; double _mu1; cin >> _mu1; //cin.ignore (std::numeric_limits...std::streamsize>::max(), '\n'); double _sigma1; cin >> _sigma1; //cin.ignore (std::numeric_limitsstd...::streamsize>::max(), '\n'); double _mu2; cin >> _mu2; //cin.ignore (std::numeric_limitsstd::streamsize...>::max(), '\n'); double _sigma2; cin >> _sigma2; //cin.ignore (std::numeric_limitsstd::streamsize>::
'\n' = " std::setprecision(std::numeric_limitsstd::setprecision(std::numeric_limitsdouble>::digits10 + 1) double> double> = " std::setprecision(std::numeric_limitsdouble>::digits10...if(std::abs(v) > std::numeric_limits::max() / p) // v * p would overflow throw std::overflow_error...::numeric_limits::max() / p) return v; // v * p would overflow if(my_abs(v) * p > std::numeric_limits
Supervisor.hpp> #include #include #include #include using namespace std...x; double z; double translation[3]; }; Driver::Driver() { timeStep = 128; x = 0.1f; z = 0.3f...getMotor("left wheel motor"); motors[1] = getMotor("right wheel motor"); motors[0]->setPosition(std...::numeric_limitsdouble>::infinity()); motors[1]->setPosition(std::numeric_limitsdouble>::infinity...Slave::boundSpeed(double speed) { return std::min(maxSpeed, std::max(-maxSpeed, speed)); } void Slave
或许可以考虑用一台性能更好的机器测试下 该 C++ 版本代码编译速度很快，供参考 #include #include #include using namespace std...(n - 1.99999999999999 numeric_limitsDOUBLE>::epsilon()) return -1.0; max = n; tem = n / 2.0...; while(fabs(tem - (floor(tem))) numeric_limitsDOUBLE>::epsilon()) { DPRINT("prime factor is：%...lf\n", 2.0); n = tem; tem = n / 2.0; } if(fabs(n-1.0) numeric_limitsDOUBLE>::epsilon())...return 2.0; for(i=3.0; i<=max; i+=2.0) { if(fabs(n-i) numeric_limitsDOUBLE>::epsilon()) {
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