我有一个读取.msg文件并提取正文和附件的C#应用程序。但是当我试图加载一个.eml文件时,应用程序崩溃了。我像这样加载文件:
MailItem mailItem = (MailItem)outlookApp.CreateItemFromTemplate(msgFileName);
mailItem.SaveAs(fullFilename, OlSaveAsType.olHTML); // save body in html format
for(int i = 0; i < mailItem.Attachments.Count; i++)
mailItem.Attachment
我正在向我的网络发送批量电子邮件通知,并且我使用的SMTP出现问题。
问题是,对于我使用的任何电子邮件帐户,它会发送大约30-40封电子邮件,然后我会收到以下错误:
...Mailbox不可用。服务器响应为:此电子邮件未被接受,请与您的电子邮件托管提供商联系。
有什么想法吗?
谢谢
代码-Windows服务:
public SMTP()
{
client = new SmtpClient(host);
client.UseDefaultCredentials = false;
client.Credentials = new N
我有一个html文件,它使用JavaScript创建一个eml文件,然后按一下按钮下载它。如果我尝试下载而不做任何更改,它将显示message.eml has been blocked because this type of file can harm your system。
现在,如果我修改注册表中的.eml路径并向其添加{"file_extension":"eml","domain":"domain.com"},我就可以下载并打开这个{"file_extension":"eml","
我正在使用Javamail1.5.6实现一个.eml解析器,我已经开始从复制javamail中提供的一个示例。
我正在测试一个eml,它包含另一个eml,这是一个摘录:
MIME-Version: 1.0
Date: Tue, 30 Apr 2019 16:20:45 +0200
Message-ID: <CA+fLqEW8TUfSxih9DTp2WXa63pS7wf1eZiro_9k1XS4AShN5Zg@mail.gmail.com>
Subject: Message with an eml as attachment
From: a b <ab@gmail.com>
在运行此查询时,我遇到了错误"Divide by zero error encountered“。
> SUM(CASE WHEN EML_DateSent IS NOT NULL THEN 1 ELSE 0 END) AS [Sends],
(SUM(CASE WHEN EML_DateViewed IS NOT NULL OR EML_DateClicked IS NOT NULL THEN 1 ELSE 0 END)) * 100 / SUM((CASE WHEN EML_Datesent IS NOT NULL THEN 1 ELSE 0 END))
以下是我的查询示例:
SELECT ...
TRIM(eml.fxeml1) as "Email Address"
FROM pfship
LEFT JOIN mstfxem fax
ON fax.fxco=pfship.cshco AND fax.fxdiv=pfship.cshdiv AND fax.fxsold=pfship.cshsld
AND fax.fxtype='C' AND TRIM(fax.fxfax1) <> '' AND fax.fxdept LIKE '*F%'
LEFT JOIN mstf
好的,我有一个文件文件夹,如下所示
ERROR WITH Position Post_20162602_022046.eml
ERROR WITH Position Post_20162602_032048.eml
ERROR WITH Position Post_20162602_042050.eml
ERROR WITH Position Post_20162602_052108.eml
ERROR WITH Position Post_20162602_062109.eml
ERROR WITH Position Post_20162602_012110.eml
ERROR WITH P
我正在尝试将下面的SQL查询转换为Linq。
select eg.userid, eg.groupid, count(r.RID) as RecipientCount
from eg
join g on eg.groupid = g.groupid
join r on g.RID = r.RID
where eg.UserId = '7F813844-3B93-418E-8141-654082C4E37D'
and eg.IsDeleted = 0
and r.Isdeleted = 0
group by eg.groupid
上述查询在SQL中正确运行。
我的Linq