我是第一次接触perl.Below,这是我使用perl访问目录的代码
#!/usr/bin/perl
# Populate the hashMap
# keys --> directories to clean
# attributes --> days to keep.
print "<-------------------------------------------------------->";
print " Touching of folders Started ";
touch `/
我想做一个带有触摸输入的小游戏,这是我为它做的代码:(这是在Update方法中)
//Check if Input has registered more than zero touches
if(Input.touchCount > 0){
//Store the first touch detected.
Touch myTouch = Input.touches[0];
//Check if the phase of that touch equals Began
我尝试在ubuntu11.04中安装java,我下载了"jdk-1_5__22-linux-i586.bin“,为此我使用了教程和
# sudo mv jdk-1_5_0_22-linux-i586.bin /usr/lib/jvm
# cd /usr/lib/jvm
# chmod +x jdk-1_5_0_22-linux-i586.bin
# ./jdk-1_5_0_22-linux-i586.bin
当我执行命令# ./jdk-1_5_0_22-linux-i586.bin时,我得到了以下错误消息
Do you agree to the above license terms?
我创建了一个sknodeshape。如何检测我制作的形状是否被触摸(单击)?
下面是代码:(我已经解决了)
//metung_babi is the name of the SKShapeNode
UITouch *touch = [touches anyObject];
CGPoint nokarin = [touch locationInNode:self];
SKNode *node = [self nodeAtPoint:nokarin];
if ([node.name isEqualToString:@"metung_babi"]) {
NSlog(@
考虑一下这个makefile:
.PHONY: all
all: dummy test
ulimit -s
include dummy
dummy: test
touch dummy
当我运行它时,我得到:
$ make -v
GNU Make 4.1
Built for x86_64-pc-linux-gnu
Copyright (C) 1988-2014 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.ht
切换到Ubuntu13.10之后,我需要为更新的内核编译一个设备驱动程序。调用make会导致两个错误:
error: implicit declaration of function ‘kzalloc’
error: implicit declaration of function ‘kfree’
相同的make命令在Ubuntu13.04中运行良好,但现在失败了。我还检查了是否存在
KDIR := /lib/modules/$(shell uname -r)/build
它在Makefile中使用,解析后成为/lib/modules/3.11.0-18-generic/build。与这个相比
这个问题把我逼疯了。我肯定我做错了什么但我搞不懂。
我有一个静态的OnTouchListener,我把它附加到线性布局中包含的一些相同的复合视图对象的TextView上。此侦听器位于帮助器类中。
public static View.OnTouchListener getValueTouchListener() {
return new View.OnTouchListener() {
private int lastY;
private int lastX;
@Override
public boolean o
当我使用:wq时,我使用vim在/home/guoyanzhang中创建sa.sh,警告程序如下:
"sa.sh" E212: Can't open file for writing
Press ENTER or type command to continue
my system infomation is as follows:
guoyanzhang@debian:~$ lsb_release -a
No LSB modules are available.
Distributor ID: Debian
Description: Debian GNU/L
我想要自动清除最古老的日志文件,首先在嵌入式系统中,时钟可能会被重置(所以文件时间是无用的)。我正在寻找一个简单的shell脚本,以找到最新的文件,以便我知道什么不删除。他们采用以下形式:
LogFileTypeA.log
LogFileTypeA.log.0
LogFileTypeA.log.1
LogFileTypeB.log <-- this is the latest of Type B
LogFileTypeA.log.2
LogFileTypeC.log
LogFileTypeC.log.0 <-- this is the latest of Type C