如何在PHP中为单个变量分配多个值?
我正试着做这个
$IP = '111.111.111.111' || '222.222.222.222' || '333.333.333.333';
if ($_SERVER['REMOTE_ADDR'] != $IP) {
echo "Your IP is not on the list";
这样做合适吗?
或者我应该把它们放在这样的数组里
$IP = array('111.111.111.111', '222.222.222.222', &
所以解决了问题,但现在,在我知道如何将字符串拆分成数组之后,我希望这个数组是二维的。当我想打印我收到的第二个维度时
java.lang.ArrayIndexOutOfBoundsException: 17
at IOControl.ReadCsvFile.fillIndex(ReadCsvFile.java:17)
at IOControl.ReadCsvFile.<init>(ReadCsvFile.java:89)
at en.window.Main.main(Main.java:48)
我发现这是因为我在我的数组里读得太远了.但是为什么呢?我的数组声明:
St
查询:
SELECT
dbo.tblDivision.DivisionName, dbo.tblDistrict.DistrictName,
case
when Gender = 'Male'
then count(Gender)
end as male,
case
when Gender = 'female'
then count(Gender)
end as female,
UnitEName
FROM
dbo.tblDistrict
INNER
例如,我有两个日期:
var first = '2013-07-30';
var second = '2013-08-04';
如何显示first和second之间的所有日期?这应该会返回给我:
2013-07-30
2013-07-31
2013-08-01
2013-08-02
2013-08-03
2013-08-04
在PHP中,我可以使用while循环将日期转换为strtotime。但是我如何在jQuery中做到这一点呢?我想把这个放在数组里。
我在App文件夹中创建了一个名为Helper.php的帮助文件。
app/Helper.php
<?php
namespace App;
use Illuminate\Support\Facades\DB;
class Helper {
public function get_username($user_id)
{
$user = DB::table('users')->where('userid', $user_id)->first();
return (isset($user-&
执行代码:
SELECT sr2.CLASSIFICATIONID, COUNT (sr2.CLASSIFICATIONID) FROM SR sr2
GROUP BY (CLASSIFICATIONID)
ORDER BY COUNT (sr2.CLASSIFICATIONID) desc;
完美无缺。试图在没有任何列选择的情况下连接额外的表:
SELECT sr2.CLASSIFICATIONID, COUNT (sr2.CLASSIFICATIONID) FROM SR sr2
LEFT JOIN CLASSSTRUCTURE cl on cl.CLASSSTRUCTUREID=sr2.
我试图将一个对象数组拆分为包含32个对象的较小数组。最后把剩下的东西放进数组里。
这是我正在使用的代码
int a = sharedManager.inventoryArray2.count;
float b = a / 33;
int c = ceilf(b);
NSMutableArray *arrayOfArrays = [NSMutableArray array];
int from = 0;
int to = 31;
for (int e = 0; e <= c; e++) {
if (sharedManager.inventoryArray2.count <
我有这个PHP regex匹配:
preg_match_all('/(\d+)(?:\.(?=(\d+)))?/', "43.3", $matches, PREG_SET_ORDER);
这(至少在我看来)意味着:
Match one or more numbers as a group, and if there is a '.' after that
group followed by a group of numbers, match those too, but ignore the '.'.
因此,可能的字符串是:
1