我有一个函数,用来转换距离lat/long的距离,但我需要使用Pythagoras函数中的x和y数据来确定这一点。让我用一个传感器提供的JSON数据的例子来说明一下。为了计算出与参考点之间的距离,我需要使用Pythagoras,然后将数据转换回lat/long,这样我的分析工具就可以显示它。output_file = 'position_data_blob_14' + str(output_nr) + '.csv' #output file name may be changed
def <em
multiplication, division, squarePower, cubePower, numPower, squareRoot, cubeRoot, numRoot, randomNum, pythagoras: float, z : int) : response = (f"The hypotenuse of side {x} and side {y} is {pythagoras/y)
return r
int pythagoras(double a, double b){
double a2; double c2; double kflaeche; double r = c; //c is from "int pythagorasprintf("Kreisradius: %2.2f Flaecheninha