鸽笼原理（也称抽屉原理） 简单的表述如下，这个原理看起来非常通俗，好像是在说一句废话一样，然而数学就是这样，总是需要证明一下。
40101 LOCAL */ TABLES': Lock wait timeout exceeded; try restarting transaction (1205)分析这个报错一眼就能看出来是 执行...(查看对应慢日志可以找到对应慢sql, 可以看看执行计划是否使用了索引)1205 只有sql执行阶段超长才会遇到, 未提交的事务不会导致这个问题.如果无法优化sql/建索引的话, 那就只有修改备份时间或者增大超时时间
题意：有n个城市，它们由一个污水处理系统连接着，每个城市可以选择 1、将左边城市过来的污水和右边城市过来的污水连同本身的污水排到河里 >V< 2、将左...
编写一个 SQL 查询，以查找每个月和每个国家/地区的已批准交易的数量及其总金额、退单的数量及其总金额。
语句应该是这样的： update user set uname = 'zhangsan' where uid = 1 如果执行这条sql语句，发现一直处于处理中的状态，然后等一定时间（超时）后报错[Err] 1205
查看事物表: select * from information_schema.innodb_trx;
项目 https://github.com/hu3rror/memos-on-fly 准备工作 注册FLY.IO 用以部署memos 注册B2C https://www.backblaze.com/...其他系统请参照官方 新建APP 初始化 flyctl launch 按照提示选择会生成一个FLY.TOML文件 编辑FLY.TOML 添加以下 [build] image = "ghcr.io/hu3rror
； 3、在编译项目代码时，也可以使用mingw； 工具下载 广大研究人员可以使用下列命令将该项目源码克隆至本地： git clone https://github.com/Bl4ckM1rror...反病毒产品扫描结果 工具代码在antiscan.me上的扫描结果如下（2022年01月08日）： 项目地址 FUD-UUID-Shellcode： https://github.com/Bl4ckM1rror
timeout exceeded; try restarting transaction mysql> insert into tt value(110, 'cd', 22); ERROR 1205...wait timeout exceeded; try restarting transaction mysql> insert into tt value(95, 'ab', 13); ERROR 1205...wait timeout exceeded; try restarting transaction mysql> insert into tt value(105, 'bc', 18); ERROR 1205...wait timeout exceeded; try restarting transaction mysql> insert into tt value(120, 'cd', 23); ERROR 1205...; try restarting transaction mysql> update tt set age = 16 where name = 'bb'; ERROR 1205 (HY000): Lock
rror Invalid argument <CN="WDKTestCert Qis,132035943314435562" | 25C85585B7D0F973D43F7931BDACA9954EBED57A
30000','AC'); insert into emp values(1204,'prasanth','php dev','30000','AC'); insert into emp values(1205...','hyd'); insert into emp_add values(1204,'78B','old city','sec-bad'); insert into emp_add values(1205...ac.com'); insert into emp_conn values(1204,'9988774','prasanth@ac.com'); insert into emp_conn values(1205...manisha, preader, 50000, TP 1203, kalil, php dev, 30000, AC 1204, prasanth, php dev, 30000, AC 1205...1202, 108I, aoc, sec-bad 1204, 78B, oldcity, sec-bad 1205, 720C, hitech, sec-bad
题目 有如下一张表G1205 希望查询出至少连续出现4次的数字，预计结果为： 该如何写这个SQL？...测试数据 CREATE TABLE G1205 (ID INT, Num INT ) INSERT INTO G1205 VALUES (1,1), (2,1), (3,1), (4,2), (5,2
/** * @author keying * @date 2022-12-05 21:31:47 */ public interface Callback1205 { void append...2022-12-05 21:33:10 */ public class Write20221205 { public void write(String filename, Callback1205...callback1205) { FileWriter fileWriter; try{ fileWriter = new FileWriter...(filename,true); callback1205.append(fileWriter); fileWriter.flush();...void listener(); } /** * @author keying * @date 2022-12-05 22:29:50 */ public class ButtonMain1205
:01:12 server id 352148329 end_log_pos 415 CRC32 0xe61e4415 Query thread_id=1477446 exec_time=0 e rror_code...:01:12 server id 352148329 end_log_pos 499 CRC32 0xd51c509c Query thread_id=1477446 exec_time=0 e rror_code...:01:12 server id 352148329 end_log_pos 583 CRC32 0x17e3871d Query thread_id=1477446 exec_time=0 e rror_code
RROR: Could not create cache adapter error=cache factory not found: factory for cache adapter
salary 1201 288A vgiri jublee 1202 108I aoc sec-bad 1203 144Z pgutta hyd 1204 78B old city sec-bad 1205...,manisha,Proof reader,50000,TP 8 1203,khalil,php dev,30000,AC 9 1204,prasanth,php dev,30000,AC 10 1205...,manisha,Proof reader,50000,TP 8 1203,khalil,php dev,30000,AC 9 1204,prasanth,php dev,30000,AC 10 1205...TP 9 1203 khalil php dev 30000.0 AC 10 1204 prasanth php dev 30000.0 AC 11 1205...~]$ hadoop fs -cat /sqoop_test/table_emp/queryresult4/part-m-00000 2 1204 prasanth php dev 3 1205
废话不多说，先直接上体验结果： 体验地址：https://huggingface.co/spaces/xinyu1205/Recognize_Anything-Tag2Text 看过笔者文章的同学应该已经发现...，之前也有介绍过一款有类似功能的项目： MiniGPT-4：使用先进的大型语言模型提升视觉语言理解 本项目的github地址为：GitHub - xinyu1205/Recognize_Anything-Tag2Text...Recognize_Anything-Tag2Text: Code for the Recognize Anything Model and Tag2Text Model: https://github.com/xinyu1205...Prompt-Can-Anything [17] Recognize Anything Model (RAM) Tag2Text web demo : https://huggingface.co/spaces/xinyu1205...IDEA-Research/Grounded-Segment-Anything [22] Tag2Text web demo : https://huggingface.co/spaces/xinyu1205
文章目录 抽屉原理 例题 HDU-1205 POJ-2356 抽屉原理 ---- 抽屉原理又称鸽巢原理：把 n+1个物品放进 n个盒子里，那么至少有一个盒子包含两个及以上的物品。...例题 HDU-1205 ---- HDU-1205 吃糖果 Problem Description HOHO，终于从Speakless手上赢走了所有的糖果，是Gardon吃糖果时有个特殊的癖好，就是不喜欢将一样的糖果放在一起吃
manisha, preader, 50000, TP 1203, kalil, php dev, 30000, AC 1204, prasanth, php dev, 30000, AC 1205...| 30000 | AC | | 1204 | prasanth | php dev | 30000 | AC | | 1205
+aid+'","imei":"","k":"hyFEc","mac_address":"10:bf:48:d0:bf:3f","model":"Nexus 7","resolution":"800x1205...imei":"","s":"'+aes.md5(bp)+'","mac_address":"10:bf:48:d0:bf:3f","model":"Nexus 7","resolution":"800x1205...:"111849acc1dd0b21","imei":"","mac_address":"10:bf:48:d0:bf:3f","model":"Nexus 7","resolution":"800x1205...mac_address","10:bf:48:d0:bf:3f"); v3.put("model","Nexus 7"); v3.put("resolution","800x1205...imei":"","k":"hyfr6iyPZMZfJFEc","mac_address":"10:bf:48:d0:bf:3f","model":"Nexus 7","resolution":"800x1205
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