我只是被这个代码弄糊涂了:
print("Welcome to Healthometer, powered by Python...")
miles = input("How many miles can you walk?: ")
if float(miles) <= 0:
print("Who do you think you are?!! Go and walk 1000 miles now!")
elif float(miles) >= 10:
print("You are very healthy!
我只是简单地把一个字符向量化了。问题是,柠檬化在单词之间创造了一个由破折号统一的空间(例如。短期变成短期)。我的字符向量充满了这些词,所以我想找到一种方法来消除这种扭曲。
让我举一个例子:
text <- c("Stackoverflow is a great website where you can find great and very skilled people who are so kind to solve your coding problems. In the short-term is a very good thing because you can spe
我有一个文本文件,格式如下:
<seg id="1"> They are the same thing. Let's shoot them both. </seg>
<seg id="1"> We can't wait for you to move back either. </seg>
<seg id="2"> You seem quite uptight. </seg>
<seg id="3"> Doe
这是我原来的字符串:-
$data = "<br />
Q.156) Direction (156–160): Study the given pie-charts carefully to answer the questions that follow: <br />
Breaking up :- Number of Employees working in Different Departments of an Organisation, the Number of Males and the Number of Employees Who Recent
这个问题难倒了我,但我已经解决了这个问题,并将我的答案发布出来。
我有一个名为Parent的基类
父级
package Parent;
sub new {
my $c = shift;
my $s = {}, bless $s, $c;
return $s;
}
sub who {
return "parent";
}
1;
这个父类公开了一个方法:who。
我编写了两个子类:Child和Freak。只有Child会覆盖who。
孩子
package Child;
use base 'Parent';
sub who {
我需要根据以下模式检查任何句子:
A sentence that consist of two or more questions
举个例子,下面的句子都与这个模式相匹配:
why do you look at me? Are you alright?
I am sick. How are you?. Well you do not have to answer it. what's up?
How are you?I am sick.what's up? Well you do not have to answer it.
因此,由于它对我来说有点复杂,我试着只识别一
我正在寻找一种按排序顺序对所有变量的值进行排序的方法。
预期结果:将va的值附加到totalList,然后添加vb's value..and等。然后将totalList转储到一个泡菜文件中。
import pickle
import time
import os
import re
v0 = ["r0", "hello","hello there","hi there","hi", "hey","good to see you"]
v1 = ["r1", &
我有这个字符串:
"“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth"
我成功地把它剥离成这样:
“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth
使用此正则表达式:
/^"(.*)"/
现在,我需要去掉两个换行符,并删除多余的空格。这是我想要返回的:
=> "It's hard to beat a person who never gives up.
我创建了下面的模型,作者是创建它的用户,还有标题和描述,很少有其他字段。
from django.db import models
from django.conf import settings
from django.utils import timezone
# Create your models here.
class Author(models.Model):
name = models.CharField(max_length=200)
added_by = models.ForeignKey(
settings.AUTH_USER_MODE
我刚开始编码,想通过制造一个不和谐的机器人来挑战自己。我在最后定稿上有困难。我想让它知道用户是谁,谁用特定的白色检查反应来响应第一组消息。然后,我想使用这个列表,结合内置计时器,在计时器完成时通知相关人员。我正在使用python和discord.py库。
import os
import discord
from discord.ext import commands
#starting the setup for the discord bot
client = discord.Client()
#login for the bot
@client.event
async def on
我一直试图从列表中显示的函数中获取数据,我尝试过使用list.append,但是我一直在获取错误,我做错了什么?
def pick_up():
name=input("Good Afternoon, who would you like to pick up? ")
additional_student=input(f"Is {name} the only person you want to pick up ?YES/NO")
if additional_student == "Yes":
我正在尝试使用document.createElement向文档中添加一个新段落。这对我没用。
HTML文件:
<section class="first">
<h2>Properties Tutorial</h2>
<p>No, no, no. A vigilante is just a man lost in scramble for his own gratification. He can be destroyed or locked up. But if you make yourself more th
我有一个充满引号的数组,在加载时会显示一个随机引号。我遇到的问题是,当我只加载了两个引号时,一切都很好,但当我添加整个列表时,它不再运行。
这是工作的代码-
<div id="quotes">Quotes</div>
<script type="text/javascript">
var quotes = [
"<i>Some people feel the rain. Others just get wet.</i><br><b>Bob Marley<
我正在寻找一个Regex来匹配包含一个或多个and的OR运算符之间每句话的全文,当且仅当一个或多个and在两个or之间的句子中。例如:
这应该是匹配的
OR "Message:\"An Arm and a Leg \<Meaning\>: Something that is extremely expensive.\"" AND "Message:\"Jaws of Death \<Meaning\>: Being in a dangerous or very deadly situation.\"" OR
这个程序要求用户输入三次,并根据输入计算chmod。我在守则中包括了一些问题和澄清意见。
如果可能的话,我想让这些问题得到解答,并帮助缩短if ... in ...部分。
'''
This program asks the user for input three times, and based on that input, calculates the chmod.
'''
'''
This is a simple function that prevents me from repeating myself.
Us
我正在从记事本上读台词。当我使用visual basic中的排序函数对它们进行排序时,我注意到结果不准确。
For example
hello i am who 1
I am who hello 14
am hello who I 13
我需要对第五列进行排序,你知道在visual basic中怎么做吗?
所以,我使用的是Bukkit API。基本上,我在寻找要调用的PlayerInteractEvent,然后在那之后我做了一堆事情。但是,当我收到通知说我实际上踢了这个块时,我没有得到任何消息,即使它在我的代码中编译时没有错误。我也没有从控制台得到异常。下面是我的代码:
@EventHandler(priority=EventPriority.HIGH)
public void onPlayerInteract(PlayerInteractEvent event, final Player who, final Action action,
final ItemStack it
对于哥伦比亚的Observatorio,我使用CLP(R) (在SWI- Fiscal1中)编写了一个简单的税收最小化问题的代码。我想使用minimize/1首先找到最小的解。相反,它首先列出了更大的解决方案。代码如下:
:- use_module(library(clpr)).
deduction(_,3). % Anyone can take the standard deduction.
deduction(Who,D) :- itemizedDeduction(Who,D). % Or they can itemize.
income(joe,10).
我创建了两个veth对,并将它们连接到同一座桥上。但是,它们不响应ping请求。这里是ubuntu 20.04。
# create the interfaces and bridge
sudo ip link add br0 type bridge
sudo ip link add i0 type veth peer name i0-p
sudo ip link add i1 type veth peer name i1-p
# connect veth peers into bridge as well as physical interface
sudo ip link set e
我得到了这个输出。输出中显示的数字是post.user.id。
如果气泡是不同的,它应该来回切换。
但它会判断它是同一个人即使不是。
为什么?
电流输出
2 Good, you? > Person B
1 How have you been? > person A
2 What's up? > person B
Person A < Hello!!!! 1
我不是这个输出
2 Good, you?
#include <stdio.h>
#include <assert.h>
#include <stdlib.h>
#include <string.h>
struct Person {
char *name;
int age;
int height;
int weight;
};
struct Person *Person_create(char *name, int age, int height, int weight)
{
struct Person *who = malloc(sizeof(
我有以下数据:
> head(bigdata)
type text
1 neutral The week in 32 photos
2 neutral Look at me! 22 selfies of the week
3 neutral Inside rebel tunnels in Homs
4 neutral Voices from Ukraine
5 neutral Water dries up ahead of World C
是否有可能让下面的示例工作,以便通过标量变量存储和调用子例程的名称?
use strict;
use warnings;
sub doit {
my ($who) = @_;
print "Make us some coffee $who!\n";
}
sub sayit {
my ($what) = @_;
print "$what\n";
}
my $action = 'doit';
$action('john');
使用“美丽汤”,我正在抓取以下网页来源:
<div>
<p class="introduction"> Manchester City's Fabian Delph limped off in the first minute of England Euro 2016 qualifier against Switzerland with a suspected hamstring injury. </p>
<p> The 25-year-old midfielder, who signed f