10个Python字符串处理技巧和窍门（2）

s1 = 'perpendicular'
s2 = 'pen'
s3 = 'pep'

print('\'pen\' in \'perpendicular\' -> {}'.format(s2 in s1))
print('\'pep\' in \'perpendicular\' -> {}'.format(s3 in s1))

'pen' in 'perpendicular' -> True
'pep' in 'perpendicular' -> False

s = 'Does this string contain a substring?'

print('\'string\' location -> {}'.format(s.find('string')))
print('\'spring\' location -> {}'.format(s.find('spring')))

'string' location -> 10
'spring' location -> -1

s1 = 'The theory of data science is of the utmost importance.'
s2 = 'practice'

print('The new sentence: {}'.format(s1.replace('theory', s2)))

The new sentence: The practice of data science is of the utmost importance.

countries = ['USA', 'Canada', 'UK', 'Australia']
cities = ['Washington', 'Ottawa', 'London', 'Canberra']

for x, y in zip(countries, cities):
print('The capital of {} is {}.'.format(x, y))

The capital of USA is Washington.
The capital of Canada is Ottawa.
The capital of UK is London.
The capital of Australia is Canberra.

from collections import Counter
def is_anagram(s1, s2):
return Counter(s1) == Counter(s2)

s1 = 'listen'
s2 = 'silent'
s3 = 'runner'
s4 = 'neuron'

print('\'listen\' is an anagram of \'silent\' -> {}'.format(is_anagram(s1, s2)))
print('\'runner\' is an anagram of \'neuron\' -> {}'.format(is_anagram(s3, s4)))

'listen' an anagram of 'silent' -> True
'runner' an anagram of 'neuron' -> False

def is_palindrome(s):
  reverse = s[::-1]
if (s == reverse):
return True
return False

s1 = 'racecar'
s2 = 'hippopotamus'

print('\'racecar\' a palindrome -> {}'.format(is_palindrome(s1)))
print('\'hippopotamus\' a palindrome -> {}'.format(is_palindrome(s2)))

'racecar' is a palindrome -> True
'hippopotamus' is a palindrome -> False