我在这里得到了这个有效的代码:
$(document).ready(function(){
var ajaxRequest; // The variable that makes Ajax possible!
try {
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e) {
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
$('#response').hide();
$('#addroom').click(function(){
var url = "./scripts/addnew_room.php";
var room_num = document.getElementById('rm_num').value;
var room_type = document.getElementById('rm_type').value;
var tosend = "&rm_num="+room_num+"&rm_type="+room_type;
ajaxRequest.open("POST", url, true);
ajaxRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4 && ajaxRequest.status == 200) {
var return_data = ajaxRequest.responseText;
document.getElementById("response").innerHTML = return_data;
}
}
ajaxRequest.send(tosend);
$('#response').show();
document.getElementById("response").innerHTML = '<img src="./ajax-images/ajax-loader.gif">';
});
});谁能告诉我为什么它没有发送变量到POST方法中,即使我设置了POST方法,它仍然使用GET方法并扰乱我的页面!
发布于 2012-10-08 12:42:11
您可以使用下面这样的内容
$.POST("url.com", {name: "John", location: "Boston"}, function(){
})POST()是一个jquery函数
您也可以使用jquery ajax()函数
$.ajax({
type:"POST",
url:"url.php",
data: { name: "John", location: "Boston" },
}).done(function(data){
// this is very simple to get or post data
$("#response").html(data);
})发布于 2012-10-08 12:47:09
最干净的方法就是使用jQuery的漂亮的$.post()函数:
$(document).ready(function() {
$('#response').hide();
$('#addroom').click(function() {
$('<img />', {src: 'ajax-images/ajax-loader.gif'}).appendTo('#response');
$.post({
url: 'scripts/addnew_room.php',
data: {
rm_num: $('#rm_num').val(),
rm_type: $('#rm_type').val()
},
success: function(response) {
$('#response').html(response);
}
});
});
});发布于 2012-10-08 12:45:57
或者像这样的东西
ajax = $.ajax({
type: "POST",
url: "your_php_page.php",
data: "a=1&b=2",
success: function(msg){
//success handler
},
error: function(msg){
//error handler
}
});https://stackoverflow.com/questions/12775427
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