blocks|key|1593888|text|$.post(url,+data,+callback,+"json");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1593889|http://docs.jquery.com/Ajax/jQuery.post|unstyled|offset|length|1593890|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|13|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|Q|8|@]|9|@$G|R|H|S|1|T]]|A|$]]|$1|I|3|-4|5|F|7|U|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|E]]]]

<pre><code>$.post(url, data, callback, "json");
</code></pre>

<a href="http://docs.jquery.com/Ajax/jQuery.post" rel="nofollow">http://docs.jquery.com/Ajax/jQuery.post</a>

blocks|key|1994767|text|$('#form_edit_item').submit(

function()+{
++++alert("submitting");
++++$.post("update_item.php",+{
++++++++star+:+"2"
++++});
});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1994768|删除{star+:+"2"}后面的逗号。尝尝这个。|unstyled|offset|length|style|CODE|1994769|entityMap^0|0|2|C|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>$('#form_edit_item').submit(

function() {
 alert("submitting");
 $.post("update_item.php", {
 star : "2"
 });
});
</code></pre>

Remove the trailing comma after <code>{star : "2"}</code>. Try this.

blocks|key|1994813|text|您可以使用ajax|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1994814|++++++++$.ajax({
++++++++++++type:+"POST",
++++++++++++url:+"update_item.php",
++++++++++++data:+{
++++++++++++++++star:+"2"+//+or+'star:+$('#id').val()',+or+any+other+value
++++++++++++}
++++++++}).done(function(+msg+)+{
++++++++++++//+do+it+when+its+done+or+do+nothing
++++++++});|code-block|syntax|javascript|1994815|在update_item.php中，你应该使用类似这样的东西|style|CODE|1994816|<?php+$star=(isset($_POST['star'])+?+$_POST['star']+:+'');
echo+$star;+?>|1994817|如果这不起作用，尝试将POST更改为GET，这样您就可以检查通过url传递值(domain.com/update_item.php?star=2)|1994818|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/jQuery.ajax/^0|5|4|0|0|0|1|F|0|0|B|4|I|3|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|13|8|@$A|14|B|15|K|L]]|9|@]|C|$]]|$1|M|3|N|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|O|3|P|5|6|7|17|8|@$A|18|B|19|K|L]|$A|1A|B|1B|K|L]]|9|@]|C|$]]|$1|Q|3|-4|5|6|7|1C|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]]]

You could use <a href="http://api.jquery.com/jQuery.ajax/" rel="nofollow">ajax</a>

<pre><code> $.ajax({
 type: "POST",
 url: "update_item.php",
 data: {
 star: "2" // or 'star: $('#id').val()', or any other value
 }
 }).done(function( msg ) {
 // do it when its done or do nothing
 });
</code></pre>

and in <code>update_item.php</code> you should use somthing like that

<pre><code>&lt;?php $star=(isset($_POST['star']) ? $_POST['star'] : '');
echo $star; ?&gt;
</code></pre>

If this won't work, try change <code>POST</code> to <code>GET</code> so you can check passing value by url (domain.com/update_item.php?star=2)

blocks|key|5779881|text|你可以使用下面的代码，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5779882|++<form+action="../handler/AjaxHelper.php"+method="POST">

++</form>

+$(document).ready(function()+{

++++++++++++$('form').submit(function()+{

++++++++++++++++$.ajax({
++++++++++++++++++++type:+this.method,
++++++++++++++++++++url:+this.action,
++++++++++++++++++++data:+$(this).serialize(),
++++++++++++++++++++success:+function(data)
++++++++++++++++++++{
++++++++++++++++++++++++var+result+=+$.parseJSON(data);
++++++++++++++++++++++++if+(result["messageCode"]+==+'success')
++++++++++++++++++++++++{
++++++++++++++++++++++++++++alert(result["message"]);
++++++++++++++++++++++++}
++++++++++++++++++++++++else
++++++++++++++++++++++++{
++++++++++++++++++++++++++++alert(result["message"])
++++++++++++++++++++++++}
++++++++++++++++++++},
++++++++++++++++++++error:+function()
++++++++++++++++++++{
++++++++++++++++++++++++alert("Please+Try+Again");
++++++++++++++++++++}++++++++++++++++++++++++
++++++++++++++++});
++++++++++++++++return+false;
++++++++++++});
++++++++});+|code-block|syntax|javascript|5779883|在AjaxHelper.php中|offset|length|style|BOLD|5779884|$objLoginHelper+=+new+LoginHelper();
$objLoginHelper+=+unserialize($_SESSION["LoginInformation"]);
$postDate+=+date("Y-m-d+H:i:s",+strtotime($_POST['txtTopicDate']));
$dataTopics+=+array($_POST['txtTopicSubject'],+$postDate,+$_POST['ddlCategories'],+$objLoginHelper->getUserLoginId());

$result+=+array();

try+{
++++$rp+=+new+Repository();
++++$rp->SaveForumTopics($dataTopics);
++++$result["messageCode"]+=+"success";
++++$result["message"]+=+"Category+Save+Successfully";
}+catch+(Exception+$ex)+{
++++$result["messageCode"]+=+"error";
++++$result["message"]+=+$ex->getMessage();
}

echo+json_encode($result);|5779885|entityMap^0|0|0|1|E|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You can Use this code,

<pre><code> &lt;form action="../handler/AjaxHelper.php" method="POST"&gt;

 &lt;/form&gt;

 $(document).ready(function() {

 $('form').submit(function() {

 $.ajax({
 type: this.method,
 url: this.action,
 data: $(this).serialize(),
 success: function(data)
 {
 var result = $.parseJSON(data);
 if (result["messageCode"] == 'success')
 {
 alert(result["message"]);
 }
 else
 {
 alert(result["message"])
 }
 },
 error: function()
 {
 alert("Please Try Again");
 } 
 });
 return false;
 });
 }); 
</code></pre>

In AjaxHelper.php

<pre><code>$objLoginHelper = new LoginHelper();
$objLoginHelper = unserialize($_SESSION["LoginInformation"]);
$postDate = date("Y-m-d H:i:s", strtotime($_POST['txtTopicDate']));
$dataTopics = array($_POST['txtTopicSubject'], $postDate, $_POST['ddlCategories'], $objLoginHelper-&gt;getUserLoginId());

$result = array();

try {
 $rp = new Repository();
 $rp-&gt;SaveForumTopics($dataTopics);
 $result["messageCode"] = "success";
 $result["message"] = "Category Save Successfully";
} catch (Exception $ex) {
 $result["messageCode"] = "error";
 $result["message"] = $ex-&gt;getMessage();
}

echo json_encode($result);
</code></pre>

I just started picking up JQuery today, and for some reason I can't get this simple $.post to work when a form is submitted.

I want to pass the value of 2 as star to my PHP page "update_item.php".

I added an alert and saw that when I clicked submit it would give me the alert, but for some reason the value of 2 just doesn't pass to the php page. 

Here's what I have with JQuery:

<pre><code>$('#form_edit_item').submit(

 function(){ 
 alert("submitting"); 
 $.post(
 "edititem.php",
 {star: "2"}, 
 );
 }); 
</code></pre>

Here's what I have in update_item.php:

<pre><code>$star = $_POST['star'];
echo "Star value: " .$star. "";
</code></pre>

What am I doing wrong?
Your help would be very much appreciated! Thanks!

Passing a value from JQuery .post to PHP

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我今天才开始使用JQuery，由于某些原因，当表单提交时，我不能让这个简单的$.post工作。我想将值2作为星号传递给我的PHP页面"update_item.php“。我添加了一个警告，当我点击提交时，它会给我一个警告，但是由于某些原因，2的值并没有传递给php页面。以下是我对JQuery的了解：$('#form_edit_item').submit(    function(){        

问将值从JQuery .post传递到PHP
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