gitlab-ci yaml文件不会在-1返回失败
gitlab-ci yaml文件不会在-1返回失败
提问于 2020-09-30 19:01:05
我用一个简单的脚本结束了我的测试步骤，该脚本扫描一个pytest output.log，如果失败，应该以-1退出，这样作业就会变成红色而不是绿色：
scripts:
- lots of test steps
- bash -c -l "python bin/status.py --statusfile=output.log; exit $?"但是gitlab-ci-runner返回0：
20200930123055|ERROR|bin/status.py:53|failed in line:173
'========================= 2 failed, 5 passed in 16.91s =========================' so returning -1 to shell
Uploading artifacts for successful job
00:01
Uploading artifacts...
output.log: found 1 matching files and directories
Uploading artifacts as "archive" to coordinator... ok id=2750517 responseStatus=201 Created token=5Gh42zsB
Job succeeded程序正在返回正确的退出代码：
python.exe .\bin\status.py --statusfile=C:\users\mobj\Downloads\output.log
20200930124542|ERROR|.\bin\status.py:53|failed in line:99 '=================== 1 failed, 5 passed, 1 skipped in 16.20s ====================' so returning -1 to shell
$?
False
python.exe .\bin\status.py --statusfile=C:\users\mobj\Downloads\output2.log
$?
True我尝试在sh中使用bin/status.py --statusfile=output.log，但是找不到这个抱怨文件。
回答 1
Stack Overflow用户
发布于 2020-09-30 20:33:39
我发现了这个错误，原来bash包装中的;exit $?只返回到当前实例
$ /bin/bash -c -l "./bin/status.py --statusfile=/mnt/c/Users/mobj/Downloads/output.log --debug; exit $?"
20200930142836|ERROR|./bin/status.py:53|failed in line:99 '=================== 1 failed, 5 passed, 1 skipped in 16.20s ====================' so returning -1 to shell
$ echo $?
0因此，只需删除;exit $?即可使其正确：
/bin/bash -c -l "./bin/status.py --statusfile=/mnt/c/Users/mobj/Downloads/output.log --debug"
20200930142754|ERROR|./bin/status.py:53|failed in line:99 '=================== 1 failed, 5 passed, 1 skipped in 16.20s ====================' so returning -1 to shell
$ echo $?
255页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/64136190
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