blocks|key|4478377|text|您可以使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4478378|var+matchingItems+=+items.filter(function(v){return+v.name=="xyz"});|code-block|syntax|javascript|4478379|或者使用jQuery+(为了获得更好的兼容性，就像许多数组函数一样，filter或some在IE8上不可用)：|offset|length|4478380|var+matchingItems+=+$.grep(items,+function(v){return+v.name=="xyz"});|4478381|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/filter|1|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/some^0|0|0|Y|6|0|15|4|1|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@$I|Z|J|10|1|11]|$I|12|J|13|1|14]]|A|$]]|$1|K|3|L|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]|U|$5|P|Q|R|A|$S|V]]]]

You might use

<pre><code>var matchingItems = items.filter(function(v){return v.name=="xyz"});
</code></pre>

or using jQuery (for greater compatibility, as like many Array functions, <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/filter" rel="nofollow">filter</a> or <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/some" rel="nofollow">some</a> aren't available on IE8) :

<pre><code>var matchingItems = $.grep(items, function(v){return v.name=="xyz"});
</code></pre>

blocks|key|4478450|text|类似于：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4478451|$.grep(yourArray,+function(n)+{+
++++return+n.name+==+"xyz";+
});|code-block|syntax|javascript|4478452|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Something like:

<pre><code>$.grep(yourArray, function(n) { 
 return n.name == "xyz"; 
});
</code></pre>

blocks|key|648262|text|使用native+some+method|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|648263|items.some(function(el)+{+return+el.name+==+"xyz";+})|code-block|syntax|javascript|648264|使用jQuery时，您需要执行类似$.grep的操作，然后检查长度($.grep(items,+function(el){+return+el.name=="xyz";+}).length+>+1)+--这不是最佳解决方案。如果您想为那些不支持some+(并且不想使用the+polyfill)的浏览器使用库解决方案，请使用Underscore的any。|648265|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/some|1|http://api.jquery.com/jQuery.grep/|2|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/some#Compatibility|3|http://underscorejs.org/^0|9|4|2|I|0|0|0|H|6|Y|1S|3E|4|4T|3|H|6|1|3Q|C|2|4I|A|3|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]]|D|@$9|1G|A|1H|1|1I]|$9|1J|A|1K|1|1L]|$9|1M|A|1N|1|1O]]|E|$]]|$1|M|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]|W|$5|P|Q|R|E|$S|X]]|Y|$5|P|Q|R|E|$S|Z]]]]

Use the <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/some" rel="nofollow">native <code>some</code> method</a>:

<pre><code>items.some(function(el) { return el.name == "xyz"; })
</code></pre>

With jQuery, you would need to do something like <a href="http://api.jquery.com/jQuery.grep/" rel="nofollow"><code>$.grep</code></a> and then check the length (<code>$.grep(items, function(el){ return el.name=="xyz"; }).length &gt; 1</code>) - not an optimal solution. If you want to use a library solution for those browsers that don't support <code>some</code> (and don't want to use <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/some#Compatibility" rel="nofollow">the polyfill</a>), use <a href="http://underscorejs.org/" rel="nofollow">Underscore</a>'s <code>any</code>.

blocks|key|4478427|text|(function(+$+)+{
++++$.find+=+function(+array,+property,+key+)+{
++++++++var+found+=+false;
++++++++for(var+i+=+0;+i+<+array.length;+i%2B%2B)
++++++++{
++++++++++++if(+array[i][property]+==+key+)+
++++++++++++{
++++++++++++++++found+=+true;
++++++++++++++++break;
++++++++++++}
++++++++}
++++++++return+found+?+i+:+-1;
++++};
})(+jQuery+);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4478428|用法：$.find(items,+"name",+"xyz");|unstyled|offset|length|style|CODE|4478429|entityMap^0|0|3|T|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>(function( $ ) {
 $.find = function( array, property, key ) {
 var found = false;
 for(var i = 0; i &lt; array.length; i++)
 {
 if( array[i][property] == key ) 
 {
 found = true;
 break;
 }
 }
 return found ? i : -1;
 };
})( jQuery );
</code></pre>

Usage: <code>$.find(items, "name", "xyz");</code>

blocks|key|648296|text|使用jQuerys+inArray示例|type|unstyled|depth|inlineStyleRanges|entityRanges|data|648297|http://api.jquery.com/jQuery.inArray/|offset|length|648298|可能对你有帮助|648299|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|11|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@$D|Q|E|R|1|S]]|A|$]]|$1|F|3|G|5|6|7|T|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|U|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|C]]]]

Use jQuerys inArray Example

<a href="http://api.jquery.com/jQuery.inArray/" rel="nofollow">http://api.jquery.com/jQuery.inArray/</a> 

might helps you

blocks|key|88098|text|++++var+arr+=+["abc",+"xyz"+];
++++++++if($.inArray("abc",arr)+>+0){
++++++++++return+true;
++++++++}
else+
return+false|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|88099|​|unstyled|88100|将返回“搜索字符串”的索引|88101|如果没有找到，它将返回-1。|88102|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code> var arr = ["abc", "xyz" ];
 if($.inArray("abc",arr) &gt; 0){
 return true;
 }
else 
return false
</code></pre>

​

this will return the index of "searching string"

if not found, it will return -1.

I have a array of objects say <code>items</code>. I want to find item having <code>name</code> xyz.

Currently, I wrote a for loop 

<pre><code>for(var i = 0; i &lt; items.length; i++)
{
 if( items[i].name == "xyz" ) 
 {
 found = true;
 break;
 }
}
</code></pre>

Is it possible to shorten this loop to one line statement using jquery? something like this:

<pre><code>$.find(items, "name", "xyz");
</code></pre>

Find a value in an array of objects using Jquery

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个对象数组，名为items。我想找到有name xyz的物品。目前，我编写了一个for循环for(var i = 0; i < items.length; i++){ if( items[i].name == "xyz" ) { found = true; break; }}是否可以使用jquery将此循环缩短为一行语句？如下所示：$.find

问使用Jquery在对象数组中查找值
EN

回答 6

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问使用Jquery在对象数组中查找值
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