在Python中并行数组打印职员和工资
在Python中并行数组打印职员和工资
提问于 2013-04-05 00:50:33
该程序将确定最高的工资，并将其与拥有该工资数字的员工的姓名一起打印出来。
我需要做一份员工清单和另一份薪水清单。我可以找到最低/最高工资并将其打印出来，但我不知道如何打印相应的员工。让这件事变得困难的是，我们只是在第6章，我们只能使用到目前为止所学到的知识。所以我们不能使用Python提供的很多内置函数(我们甚至还没有介绍append()方法，所以我不得不使用另一种方法来添加到列表中。)也不允许使用max和min。
amount = int(input("How many employees?: "))
if amount <= 0:
print("You cannot have 0 or less.")
name = []
salary = []
length = len(salary)
mini = 200000
maxi = 0
combined = (name, salary)
for i in range(1, amount + 1):
employee = input("What is the employee's name?: ")
name += [employee]
earned = int(input("How much is the salary? It cannot be less than 0 or over $200,000: "))
while earned <= 0 or earned >= 200000:
earned = int(input("How much is the salary? It cannot be less than 0 or over $200,000: "))
mini = earned
maxi = earned
salary += [earned]
total += earned
if earned < mini:
mini = earned
if earned > maxi:
maxi = earned回答 1
Stack Overflow用户
回答已采纳
发布于 2013-04-05 01:06:54
按如下方式存储索引
amount = int(input("How many employees?: "))
if amount <= 0:
print("You cannot have 0 or less.")
name = []
salary = []
length = len(salary)
MAX_SALARY = 200000
mini = MAX_SALARY + 1
maxi = -1
mini_idx = -1
maxi_idx = -1
for i in range(amount):
employee = input("What is the employee's name?: ")
name += [employee]
earned = -1
while earned >= 0 and earned <= MAX_SALARY:
earned = int(input("How much is the salary? It cannot be less than 0 or over $200,000: "))
salary += [earned]
total += earned
if earned < mini:
mini = earned
mini_idx = i
if earned > maxi:
maxi = earned
maxi_idx = i然后，您想要的值将由
salary[mini_idx]
name[mini_idx]
salary[maxi_idx]
name[maxi_idx]页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/15817122
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