问使用$.ajax将具有不同类型的多个参数传递给MVC方法

EN

function PostForm(buttonname) {

var data = $('#form').serialize();
var finaldata = data + "&buttonclicked="+buttonname;

$.ajax({
    url: "/ControllerName/ViewName",
    type: "POST",
    data: finaldata ,
    success: success function(){},
    error : error function(){}
    });
};

<input name="buttonname" value="Name" onClick="PostForm('Name')" />

public ActionResult ViewName(List<MyObject> listOfObjects ,string buttonclicked)
{
//Obj should now contain the list of objects and button name
}

$.ajax({
    url: "/ControllerName/ViewName",
    type: "POST",
    dataType: "application/JSON",
    data: JSON.stringify($('#form').serialize())
});

[HttpPost]
public ActionResult ViewName(FormCollection formCollection)
{
     // use formCollection["yourcontrol"] to get your post value
}

function PostForm(buttonname) {

    $.ajax({
        url: "/ControllerName/ViewName",
        type: "POST",
        dataType: "application/JSON",
        data: { listOfObjects: data: $('#Form').serilize(), button: buttonname },
        JSON.stringify({ 
           listOfObjects = $('#form').serialize(),
           button : buttonname
        })
    });
};

[HttpPost]
public ActionResult ViewName(MyObject[] listOfObjects ,string button)
{

}