我真正需要的是创建函数在php发送电子邮件时,field_number 7日期是今天。如果lead_id 1 field_number 7数据是今天的话,我只需要发送例如lead_id 1的数据。当脚本将被创建时,我想将cron作业添加到这个文件中,这样它每天都会检查当天。我的mysql数据如下:

我不是程序员,但据我所知,代码必须是这样的:
//authentication for database
$hostname = "localhost";
$username = "admin";
$password = "xxxxxx";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
//select a database to work with
$selected = mysql_select_db("notification",$dbhandle)
or die("Could not select examples");
//execute the SQL query and return records
$result = mysql_query("SELECT * FROM tbl_lead WHERE pass_expiry >= DATE(NOW() + INTERVAL 1 DAY");
//variable for email message
$emailBody = "";
$headers = 'From: Pass Validity Reminder' . "\r\n" .
'Reply-To: myemail@email.com' . "\r\n" .
'Cc: ccemail@Wemail. com' . "\r\n".
'X-Mailer: PHP/' . phpversion();
$to = "myemail@email.com";
//fetch tha data from the database
while ($row = mysql_fetch_array($result))
{发布于 2017-07-13 15:18:13
考虑到图中的表结构,使用下面的SQL语句来获取所有匹配的记录
$result = mysql_query("SELECT * FROM YOURTABLENAME WHERE lead_id='1' and field_number='7' and value=CURRENT_DATE();更新:
$result = mysql_query("SELECT lead_id, form_id, field_number, value FROM YOURTABLENAME WHERE field_number='7' and value=CURRENT_DATE();以上查询将提供field_number 7的所有记录,并且value是今天的日期
while ($row = mysql_fetch_array($result)){
if($row['lead_id']==1){
//send email to all lead_id 1
}
if($row['lead_id']==2){
//send email to all lead_id 1
}
.... Add leads to whom you have to send email
}发布于 2017-07-13 14:59:48
如果您希望根据当前日期检索数据,则可以使用以下sql查询
$result = mysql_query("SELECT * FROM tbl_lead WHERE pass_expiry=CURRENT_DATE()");此查询将选择今天的所有日期数据
https://stackoverflow.com/questions/45073240
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