如何将多个图像保存到一个泡菜文件中？而泡菜文件包含图像数据(像素信息)，还是只包含图像文件的名称？
如何将多个图像保存到一个泡菜文件中？而泡菜文件包含图像数据(像素信息)，还是只包含图像文件的名称？
提问于 2022-01-16 14:08:05
我有一个名为1.jpg、2.jpg、3.jpg.11344.jpg、11345.jpg的“鸟”文件夹，其中有11345个鸟图像。我需要将这些鸟类图像保存为"filenames.pickle“，以便在远程机器学习模块中使用它。数据应以这种方式排列:数据集/列车/文件.泡菜、数据集/测试/文件.泡菜
我需要创建一个单一的泡菜文件filenames.pickle，以获得所有的11345鸟图像。我非常困惑该如何将这些图像添加到泡菜中，这样我的代码就可以获取泡菜文件，但是它最终会到达这些图像来训练机器学习模型。
from PIL import Image
import pickle
'''
I am just trying to convert one image into pickle to get an idea.
if is succefully convert into pickle then I will read all the
images inside the "bird" folder and convert all of them into one
single pickle file
'''
# converting an image into pickle
img = Image.open('059.jpg')
with open('059.pickle', 'wb') as f:
pickle.dump(img, f)
## read the pickle file
with open('059.pickle','rb') as f:
file = pickle.load(f)
print(file)
# after reading 059.pickle file :
<PIL.JpegImagePlugin.JpegImageFile image mode=RGB size=500x375 at 0x2115BE59190>
# I dont want ( <PIL.JpegImagePlugin.JpegImageFile image mode=RGB
size=500x375 at 0x2115BE59190>) this result into pickle file.
# I want pickle file to save result like this: ['59.jpg'].
## to convert whole images inside bird folder
## input folder = bird\\images\\all_images_in_jpg_format
image = "bird\\images\\"
fout = open("bird\\filenames.pickle",'wb')
pickle.dump(image,fout)
fout.close()
with open("bird\\filenames.pickle",'rb') as f:
file = pickle.load(f)
print(file)
# output : bird\images\
## the above output is wrong
'''
becasue when I am done reading all the images and create one
pickle file as "filenames.pickle:, it should save images like
this:
['01.jpg','0342.jpg','06762.jpg', '06752.jpg', '05122.jpg',
'05144.jpg', '06635.jpg','06638.jpg',
'05632.jpg',......'11345.jpg']
and after reading this pickle file, somehow model will
automatcally read the images via pickle file.
'''我不太熟悉泡菜文件和它的格式。有人能帮我吗?或者给我一些建议，我该如何处理和解决这个问题？模型将如何通过泡菜文件读取图像？泡菜文件包含什么(图像数据和像素信息，或者仅仅是图像文件的名称)，以便模型能够在训练时间内获取泡菜文件并学习图像？
回答 1
Stack Overflow用户
回答已采纳
发布于 2022-01-16 17:53:40
修改了我原来的答案。现在，我在一个文件中选择文件名，并将图像保存到另一个文件中。
from PIL import Image
import os
import pickle
from glob import glob
## to convert whole images inside bird folder
## input folder = bird\\images\\all_images_in_jpg_format
PICKLE_FILE = "bird\\filenames.pickle"
SOURCE_DIRECTORY = "bird\\images\\"
PICKLE_IMAGES = "bird\\images.pickle"
path_list = glob(os.path.join(SOURCE_DIRECTORY, "*.jpg"))
# pickle images into big pickle file
with open(PICKLE_IMAGES,"wb") as f:
for file_name in path_list:
pickle.dump(Image.open(file_name),f)
# get short names from the path list
file_list = list(
map(
lambda x: os.path.basename(x), path_list)
)
# pickle short name list
pickle.dump(file_list, open(PICKLE_FILE, 'wb'))
# test that we can reread the list
recovered_list = pickle.load(open(PICKLE_FILE,"rb"))
if file_list == recovered_list:
print("Lists Match!")
else:
print("Lists Don't Match!!!")
# read a couple images out of the image file:
display_count = 5
with open(PICKLE_IMAGES,"rb") as f:
while True:
try:
pickle.load(f).show()
display_count -= 1
if display_count <= 0:
break
except EOFerror as e:
break它可能仍然是你的教练想要个别的腌制图像，或者它不喜欢PIL使用的图像格式。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/70730835
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