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社区首页 >问答首页 >FilterRegistrationBean中可疑的URL模式?

FilterRegistrationBean中可疑的URL模式?
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Stack Overflow用户
提问于 2022-07-13 13:02:39
回答 1查看 208关注 0票数 0

最近,我在启动spring-boot应用程序时收到以下警告:

o.a.c.c.StandardContext: Suspicious URL pattern: [/rest/**] in context [], see sections 12.1 and 12.2 of the Servlet specification

定义:

代码语言:javascript
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@Bean
public FilterRegistrationBean traceFilterRegistration(HttpTraceFilter filter) {
    FilterRegistrationBean registration = new FilterRegistrationBean(filter);
    registration.addUrlPatterns("/rest/**");
    return registration;
}

问:现在的/rest/*/rest/**一样吗?这样我就可以安全地切换它了吗?我的目标显然是在rest路径下捕获任何子路径(如/rest/this/is/my/sub )。

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回答 1

Stack Overflow用户

回答已采纳

发布于 2022-07-13 14:33:57

Servlet 3.1和4.0的规范声明如下:

代码语言:javascript
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12.2 Specification of Mappings

In the Web application deployment descriptor, the following syntax is used to define
mappings:
■ A string beginning with a ‘/’ character and ending with a ‘/*’ suffix is used for
path mapping.
■ A string beginning with a ‘*.’ prefix is used as an extension mapping.
■ The empty string ("") is a special URL pattern that exactly maps to the
application's context root, i.e., requests of the form http://host:port/<contextroot>/. In this case the path info is ’/’ and the servlet path and context path is
empty string (““).
■ A string containing only the ’/’ character indicates the "default" servlet of the
application. In this case the servlet path is the request URI minus the context path
and the path info is null.
■ All other strings are used for exact matches only.
If the effective web.xml (after merging information from fragments and
annotations) contains any

这意味着模式/rest/**是无效的,应该更改为/rest/*

票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/72966802

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