问当我使用Scrapy在管道中发送通知时，电报响应400

EN

    def sendnotifications(self, token):
        cursor = self.cnx.cursor()
        req = requests
        cursor.execute("SELECT * FROM notificate WHERE token= '"+token+"'")
        notifications = cursor.fetchall()
        for notification in notifications:
            print(notification)
            productid = notification[1]
            url = notification[3]
            name = notification[2]
            old = notification[4]
            new = notification[5]
            price_difference = old - new
            percentage = price_difference / old
            percentage_str = str("%.2f" % (percentage * 100))

            message = "<b>" + name + "</b>" + "\n\n" + \
                str(old) + " TL >>>> " + \
                str(new) + f" TL - <b>{percentage_str}%</b>" + "\n\n" + \
                url + "\n\n" + \
                "https://www.hepsiburada.com/" + "ara?q=" + productid + "\n\n"

            TOKEN = "xxxxxxxxxxxxxxxxxxxxx"
            chat_id = "xxxxxxxxxxxxx"
            tel_url = f"https://api.telegram.org/bot{TOKEN}/sendMessage?chat_id={chat_id}&text={message}"
            
            try:
                r = requests.get(tel_url
                )
                print(r)
            except RequestException:
                return False
        cursor.close()
        return True