问Python请求返回200而不是301

EN

try   
    r = requests.get(url,headers={'User-Agent': ua.random},timeout=timeout) # execute a timed website request
    if r.status_code > 299: # check for bad status
        r.raise_for_status() # if confirmed raise bad status
    else:
        print(r.status_code, url) # otherwise print status code and url
except Exception as e:
     print('\nThe following exception: {0}, \nhas been found found on the following post: "{1}".\n'.format(e,url))