我对mysql查询有问题,希望有人能帮我。
我有以下表格:
CREATE TABLE USER
(
ID VARCHAR(80) NOT NULL,
REGISTRATION_DATE DATE NOT NULL,
.....
PRIMARY KEY(ID)
);
CREATE TABLE INVOICES
(
USER_ID VARCHAR(80) NOT NULL,
INVOICE_NUMBER VARCHAR(50) NOT NULL,
CREATION_DATE DATE NOT NULL,
........
PRIMARY KEY(USER_ID, INVOICE_NUMBER),
FOREIGN KEY(USER_ID) REFERENCES USER(ID)
);我需要以下功能:我选择开始日期和结束日期(时间段),例如01.02.2013-31.05.2013作为查询的参数,并希望看到:
示例:期间: 01.02.2013-31.05.2013结果集:
Month | Year | Total count of users | Count of users who created at least one invoice in this month | Count of invoices in this month
Febr | 2013 | 20 | 12 | 45
March | 2013 | 20 | 4 | 22
April | 2013 | 23 | 20 | 30
May | 2013 | 28 | 27 | 69写这样的查询可以吗?我试过这样做:
SELECT YEAR, MONTH, @VAR := @VAR + TOTS.COUNT AS USERS_TOTAL
FROM (
SELECT
YEAR(REGISTRATION_DATE) AS YEAR,
MONTH(REGISTRATION_DATE) AS MONTH,
COUNT(ID) AS COUNT
FROM USER
WHERE REGISTRATION_DATE <= '2013-05-31'
GROUP BY YEAR, MONTH
) AS TOTS, (SELECT @VAR := 0) AS INC我得到的用户总数,但只有当有一些新的注册用户。我是说,如果Ferb的用户总数。三月是二十,四月二十一日,我得到二月。
通过这个查询,我可以得到创建至少一张发票的用户的计数,但是如果计数与前几个月的计数相同,则没有任何信息:
SELECT YEAR(CREATION_DATE) as YEAR, MONTH(CREATION_DATE) as MONTH,
COUNT(DISTINCT CUSTOMER_ID)
FROM INVOICES
WHERE CREATION_DATE >= '2013-02-01' AND CREATION_DATE <='2013-05-31'
GROUP BY YEAR, MONTH通过这个查询,我可以得到选择期内每个月的发票数量:
SELECT YEAR(CREATION_DATE) as YEAR, MONTH(CREATION_DATE) as MONTH, COUNT(INVOICE_NUMBER)
FROM INVOICES
WHERE CREATION_DATE >= '2013-02-01' AND CREATION_DATE <='2013-05-31'
GROUP BY YEAR, MONTH我想在一个查询中完成这个任务,就像我说的那样,希望每个月都有信息,即使信息与前一个月相同。我怎样才能达到我想要的结果,任何想法?
发布于 2013-05-29 14:43:46
分别生成它们中的每一个都非常简单。但是,如果您想将它们放在一个查询中,这可能会很麻烦。最好是分几个步骤来完成。但这是我的尝试
SELECT
extract(MONTH FROM i.date) AS MONTH,
extract(YEAR FROM i.date) AS YEAR, count(i.*) AS Count_Invoices,
count(user.*) as count_users,
CASE (WHERE i.* IS NOT NULL COUNT u.id END) AS active_users_this_month
FROM
invoices I RIGHT JOIN users u
GROUP BY
Year, Monthhttps://stackoverflow.com/questions/16815743
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